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fenix001 [56]
3 years ago
10

Imagine you have m distinct baskets in which you’re throwing n number of balls at random. Each throw is independent of any other

throw, and every basket is equally as likely to get a ball on a throw. After the n throws, what is the probability that a given basket is empty?
Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

(\frac{m-1}{m})^n

Step-by-step explanation:

Given a basket, the probability of a ball to end there is \frac{1}{m} (because there are m baskets).

Then, the probability of a ball to end in other basket is \frac{m-1}{m}.

Finally, the probability of the basket to remain empty after n throws is

(\frac{m-1}{m})^n

This last is because, given n independets events with probability p, the probability for all of them to happen is p^n. In this case p=\frac{m-1}{m}

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svetoff [14.1K]
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6 0
3 years ago
What ratio forms a proportion with 8/36 ? <br> a. 1/4 <br> b.6/27<br> c.7/30 <br> d.2/7
Vaselesa [24]
6/27 bc (6/27)=(8/36)= 216/216= they are the same or 2/9=6/27=8/36
7 0
2 years ago
How do i find the greatest common factor of 84 and 36
Rufina [12.5K]

Answer:

What is the GCF of 36 and 84?

Find the prime factorization of 36.

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To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 3.

GCF = 12.

The common factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, and 84. We can get all the factors using the prime factorization method.

Step-by-step explanation:

7 0
2 years ago
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From the top of a vertical cliff 50 m high, the angle of depression of an object that is level with the base of the cliff is 70°
Svetlanka [38]

Answer:

The distance of the object from the base of cliff is 18.24 meters

Step-by-step explanation:

Given as :

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The distance of the object from the base of cliff = x meters

Let The angle of depression of object that level with cliff base = Ф = 70°

<u>Now, from figure</u>

Tan angle = \dfrac{\textrm perpendicular}{\textrm base}

I.e TanФ = \dfrac{\textrm AB}{\textrm OA}

Or, TanФ = \dfrac{\textrm h}{\textrm x}

Or, Tan 70° = \dfrac{\textrm 50 meters}{\textrm x meters}

Or, 2.74 = \dfrac{\textrm 50}{\textrm x}

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I,e x = 18.24 meters

So, The distance of the object from the base of cliff = x = 18.24 meters

Hence,The distance of the object from the base of cliff is 18.24 meters Answer

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Answer:

I dont have a question but thanks so much for doing that!

Step-by-step explanation:

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