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just olya [345]
3 years ago
9

If an object, beginning at rest, is moving at a speed of 700 m/s after 2.75 min, its rate of acceleration (in m/s 2) is ________

. (Assume that the rate of acceleration is constant.)
Physics
1 answer:
Sloan [31]3 years ago
4 0

Answer: 4.24m/s²

Explanation:

Acceleration is defined as change in velocity of an object with respect to time. Mathematically,

Acceleration (a) = Change in velocity/time taken

Acceleration (a) = final velocity (v) - initial velocity (u)/time taken (t)

Final velocity = 700m/s

Initial velocity = 0m/s (object beginning from rest)

Time taken = 2.75mins = (2.75 × 60)secs = 165seconds

Substituting the values in the acceleration formula a = v-u/t

a = 700-0/165

a = 4.24m/s²

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Answer: The answer for A is - v = 786.93 m/s

The answer for B is - v = 122.40 m/s

Explanation:

a) To find the average exhaust speed (v) of the engine we can use the following equation:

F = vΔm

Where:

F: is the thrust by the engine = 5.26 N

Δm: is the mass of the fuel = 12.7 g

Δt: is the time of the burning of fuel = 1.90 s

v = F×ΔT/ΔT

b) To calculate the final velocity of the rocket we need to find the acceleration.

The acceleration (a) can be calculated as follows:

a = F/M

In the above equation, m is an average between the mass of the engine plus the rocket case mass and the mass of the engine plus the rocket case minus the fuel mass:

m = (m_{engine} + m_{rocket}) + (m_{engine} + m_{rocket} - m_{fuel})}{2} = {2*m_{engine} + 2*m_{rocket} - m_{fuel}}{2} = 2*25.0 g + 2*63.0 g - 12.7 g}{2} = 81.65 g

Now, the acceleration is:

a = 5.26 N/81.65-t 10^³kg} = 64.42 m*s^²

Finally, the final velocity of the rocket can be calculated using the following kinematic equation:

v= v_{0} + at = 0 + 64.42 m*s^{-2}*1.90 s = 122.40 m/s

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