There is a basic difference<span>, because </span>mass<span> is the actual amount of material contained in a body and is </span>measured<span>in kg, gm, etc. Whereas </span>weight<span> is the force exerted by the gravity on that object mg. Note that </span>mass<span> is independent of everything but </span>weight<span> is different on the earth</span>
Answer:
339.12 m/s, 343.31 m/s
Explanation:
For main rotor
diameter, d = 14.4 m
radius, r = 7.2 m
f = 450 rev/min = 450 / 60 = 7.5 rps
Angular speed, ω = 2 x π x f = 2 x 3.14 x 7.5 = 47.1 rad/s
linear speed, v = r x ω = 7.2 x 47.1 = 339.12 m/s
For tail rotor
diameter, d = 1.6 m
radius, r = 0.8 m
f = 4100 rev/min = 4100 / 60 = 68.33 rps
Angular speed, ω = 2 x π x f = 2 x 3.14 x 68.33 = 429.13 rad/s
linear speed, v = r x ω = 0.8 x 429.13 = 343.31 m/s
Answer:
T₂ = 2482.34 N
Explanation:
Equations of balance of forces
Look at the force diagram in the attached graph:
∑Fx=0
T₂cos α -T₁senα = 0 Equation (1)
∑Fy=0
T₁cos α +T₂sinα-W =0 Equation(2)
Data
m=539 kg
g= 9.8 m/s²
W= m*g= 539 kg* 9.8 m/s²= 5282.2 N
T₁ = 1.88T₂
Problem development
in the equation (1)
T₂cos α-(1.88T₂)senα = 0 We divided the equation by ( T₂cos α)
1 - (1.88)tanα = 0
tanα= 1/(1.88)
tanα= 0.5319
α = 28°
T₂=(1.88T₂)tanα
in the equation (2)
(1.88T₂)cos α+ T₂sinα - 5282.2 =0 We divided the equation by cos α
1.88T₂+ T₂tanα - 5282.2/cos α =0
1.88T₂+ T₂tan(28°) - 5282.2/(cos 28°) =0
1.88T₂+ (0.53)T₂- 5982.46 =0
(2.41)T₂ = 5982.46
T₂ = 5982.46/(2.41)
T₂ = 2482.34 N
Answer:
(a)
(b)
Explanation:
Part (a)
The total length of copper cord L=86.3 m
The cross sectional area A=1.71×10⁻⁶m²
The resistivity of copper p=1.72×10⁻⁸Ω
Thus the resistance of extension cord is
Part (b)
The resistance of trimmer Rt=17.9 ohms
When voltage of 120V is applied then the current I is passing through series circuit is
Thus the voltage across the trimmer is:
<span>The waste products of combustion leave the internal combustion engine through the: B) Exhaust valve</span>