Question

How many moles of NaCl are created as a result of decomposing 12 grams of NaClO3? (molar mass of Na=23, Cl=35, O=16)

Answer 1

Answer: 0.113 moles of NaCl are created as a result of decomposing 12 grams of $NaClO_3$.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$   

$\text{Moles of} NaClO_3=\frac{12g}{106.5g/mol}=0.113moles$

The balanced chemical equation for decomposition of $NaClO_3$ is:

$2NaClO_3\rightarrow 2NaCl+3O_2$  

According to stoichiometry :

2 moles of $NaClO_3$ give = 2 moles of $NaCl$

Thus 0.113 moles of $NaClO_3$ give =$\frac{2}{2}\times 0.113=0.113moles$  of $NaCl$

Thus 0.113 moles of NaCl are created as a result of decomposing 12 grams of $NaClO_3$.