The reaction given is:
4Ga + P4 ---> 4GaP
The oxidation number of the reactants is zero, because they are pure elements.
The P in compounds may have oxidation states 3- or 5-. Gallium may only have oxidation state 3+.
Then, to be neutral in GaP the oxidation states are 3+ for Ga and 3- for P.
And the transference of electrons can be see in this oxidation - reduction equations:
Ga (0) - 3 e- ----> Ga (3+)
P (0) + 3e- ---> P (3-)
So, for one formula unit, 3 electrons have been transfered from each Ga atom to P atom to form one GaP unit.
Answer: 3 electrons.
Answer:
The steps with correct mechanism are given below:
C
1) CH₄(g) + Cl(g) → CH₃(g) + HCl(g) : This is a slow step.
The rate is given as: R1 = k₁[CH₄][Cl]
2) CH₃(g) + Cl₂(g) → CH₃Cl(g) + Cl(g): This is a fast step.
The rate is given as: Rate = k₂[CH₃][Cl₂]
∴ CH₄(g) + Cl₂(g) → CH₃Cl(g) + HCl(g)
Here, the slowest step will be the rate-determining step.
Explanation:
Oxidation state of Nitrogen in N2O5 is +5
Answer: Redox Reaction
Explanation:
Redox reaction is the key chemical events in an oxidation-reduction also called Redox. It is the net movement of electrons from one reactants to another
Its phosphorus (P)In writing the electron configuration for Phosphorus the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Phosphorous go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. Since the 3s if now full we'll move to the 3p where we'll place the remaining three electrons. Therefore the Phosphorus electron configuration will be 1s22s22p63s23p3.
