Answer:
the question makes no sense, no products are shown therfore all are reactants.
Answer:
5.9 × 10^-6.
Explanation:
In the arrangements of crystal solids there is likely going to be an imperfection or defect and one of the defect or imperfections in the arrangements of solids is known as the Schottky defects. The Schottky defects is a kind of lattice arrangements imperfection that occurs when positively charged ions and negatively charged ions leave their position.
So, let us delve right into the solution of the question. We will be making use of the formula below;
Wb/ W = e^ - c/ 2kT.
Where Wb/ W= fraction of lattice sites, c= energy for defect formation = 1.86 eV, and T = temperature= 623° C= 896 k.
So, Wb/ W = e ^ -1.86/ (2 × 896 × 8.62 × 10^ -5).
Wb/ W= 0.000005896557435956372.
Wb/ W=5.9 × 10^-6.
Henry law:
P = KC
P = solvent vapour pressure
K = Henry constant
C = conc of solute
So, 0.2 = 773 C
so, C = 0.2 / 773 = 2.5 x 10^{-4} molal
Answer:
+523 kJ.
Explanation:
The following data will be used to calculate the average C-S bond energy in CS2(l).
S(s) ---> S(g)
ΔH = 223 kJ/mol
C(s) ---> C(g)
ΔH = 715 kJ/mol
Enthalpy of formation of CS2(l)
ΔH = 88 kJ/mol
CS2(l) ---> CS2(g)
ΔH = 27 kJ/mol
CS2(g) --> C(g) + 2S(g)
So we must construct it stepwise.
1: C(s) ---> C(g) ΔH = 715 kJ
2: 2S(s) ---> 2S(g) ΔH = 446 kJ
adding 1 + 2 = 3
ΔH = 715 + 446
= 1161 kJ
3: C(s) + 2S(s) --> C(g) + 2S(g) ΔH = 1161 kJ
4: C(s) + 2S(s) --> CS2(l) ΔH = 88 kJ
adding (reversed 3) from 4 = 5
ΔH = -1161 + 88
= -1073 kJ
5: C(g) + 2S(g) --> CS2(l) ΔH = -1073 kJ
6: CS2(l) ---> CS2(g) ΔH = 27 kJ
adding 5 + 6 = 7
ΔH = -1073 + 27
= -1046 kJ
7. C(g) + 2S(g) --> CS2(g) ΔH = -1046 kJ
Reverse and divide by 2 for C-S bond enthalpy
= -(-1046)/2
= +523 kJ.
Answer:
Acetone
Explanation:
Chromatography has to do with the separation of substances by eluting the components of the solute using a mobile phase. The composition of the mixture to be separated decides the mixture of solvents (mobile phase) that are to be used for elution.
In this case the mixture to be separated comprises of substance A which is polar and substance B which is non polar. It is observed that the mobile phase moves B up the plate but not the polar substance, A. This means that a polar solvent such as acetone should be added to the mobile phase in order to achieve better elution of A.
