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Mekhanik [1.2K]
2 years ago
7

Et answer

Chemistry
1 answer:
Molodets [167]2 years ago
7 0

Answer:

do it yourself

mate.

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<h3><em><u>and </u></em><em><u>mark </u></em><em><u>my </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as </u></em><em><u>Brainlist </u></em><em><u>because</u></em><em><u> </u></em><em><u>marking </u></em><em><u>my </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as </u></em><em><u>Brainlist</u></em><em><u> </u></em><em><u>you </u></em><em><u>would</u></em><em><u> </u></em><em><u>not </u></em><em><u>be </u></em><em><u>losing</u></em><em><u> </u></em><em><u>anything </u></em><em><u>and </u></em><em><u>about </u></em><em><u>your </u></em><em><u>answer</u></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u>do </u></em><em><u>yourself</u></em></h3>

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Consider that the room is a closed system. Ryan uses the chemical energy in his muscles to create the energy of motion. He uses
Vilka [71]
D.

This is in accordance with the law of conservation of energy.
6 0
2 years ago
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The chemical equation, Cr + Fe(NO3)2 → Fe + Cr(NO3)3, is an example of which type of reaction?
Angelina_Jolie [31]

Answer:

Redox type

Explanation:

The reaction is:

2Cr +  3Fe(NO₃)₂ → 2Fe + 2Cr(NO₃)₃

2 moles of chromium can react to 3 moles of iron (II) nitrate in order to produce 2 moles of iron and 2 moles of chromium nitrate.

If we see oxidation state, we see that chromium changes from 0 to +3

Iron changed the oxidation state from +2 to 0

Remember that elements at ground state has 0, as oxidation state.

Iron is being reduced while chromium is oxidized. Then, the half reactions are:

Fe²⁺  +  2e⁻ ⇄  Fe    (Reduction)

Cr ⇄ Cr³⁺  +  3e⁻    (Oxidation)

When an element is being  reduced, while another is being oxidized, we are in prescence of a redox reaction.

8 0
3 years ago
Which of the following compounds' solubility will not be affected by a low pH in solution?
Whitepunk [10]

The compound solubility which will not be affected by a low pH in solution is AgBr.

<h3>What is pH?</h3>

pH is a measure of the acidity or basicity of any solution and according to the pH scale 0 to 6.9 shows the acidity, 7 is neutral and 7.1 to 14 shows the basicity of any solution.

  • AgBr is sparingly soluble in water and not soluble in acids, so if we low the pH of the solution towards the acidity its solubility not affected.
  • NiCO₃ is a basic salt and and shows solubility in the acidic medium so change in pH will affect its solubility.
  • Co(OH)₂ it is also a basic compound and shows its solubility in the acidic medium and get affected when change in pH takes place.
  • PbF₂ is a strong base and also shows solubility in the acidic medium easily, so get affected when change in pH takes place.
  • In CuS, sulphide is basic ion and whole compound shows solubility in the acidic medium and get affected when low pH of solution takes place.

AgBr is not affected by a low pH in solution.

To know more about solubility, visit the below link:

brainly.com/question/23946616

3 0
2 years ago
Read 2 more answers
How many moles are there in 3.612 x 1024 molecules of CaO?
melamori03 [73]

The number of moles in  3.612 x 10²⁴ molecules of CaO is  6 moles.

<h3>Number of moles in the molecules</h3>

The number of moles in  3.612 x 10²⁴ molecules of CaO is calculated as follows;

6.02 x 10²³ molecules = 1 mole

3.612 x 10²⁴ molecules = ?

= (3.612 x 10²⁴ ) / (6.02 x 10²³ )

= 6 moles

Thus, the number of moles in  3.612 x 10²⁴ molecules of CaO is  6 moles.

Learn more about number of moles here: brainly.com/question/15356425

3 0
2 years ago
How many milliliters of 0.50 M KOH are needed
spayn [35]

Answer:

Option D. 30 mL.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above,

The mole ratio of the acid, nA = 1

The mole ratio of the base, nB = 1

Step 2:

Data obtained from the question. This include the following:

Volume of base, KOH (Vb) =.?

Molarity of base, KOH (Mb) = 0.5M

Volume of acid, HNO3 (Va) = 10mL

Molarity of acid, HNO3 (Ma) = 1.5M

Step 3:

Determination of the volume of the base, KOH needed for the reaction. This can be obtained as follow:

MaVa / MbVb = nA/nB

1.5 x 10 / 0.5 x Vb = 1

Cross multiply

0.5 x Vb = 1.5 x 10

Divide both side by 0.5

Vb = (1.5 x 10) /0.5

Vb = 30mL

Therefore, the volume of the base, KOH needed for the reaction is 30mL.

3 0
3 years ago
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