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Mekhanik [1.2K]
3 years ago
7

Et answer

Chemistry
1 answer:
Molodets [167]3 years ago
7 0

Answer:

do it yourself

mate.

<h2><em><u>because</u></em><em><u> </u></em><em><u>doing</u></em><em><u> </u></em><em><u>work </u></em><em><u>yourself </u></em><em><u>and</u></em><em><u> </u></em><em><u>understanding</u></em><em><u> </u></em><em><u>increases </u></em><em><u>your </u></em><em><u>knowledge</u></em><em><u> </u></em><em><u>understand</u></em></h2>

<h3><em><u>and </u></em><em><u>mark </u></em><em><u>my </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as </u></em><em><u>Brainlist </u></em><em><u>because</u></em><em><u> </u></em><em><u>marking </u></em><em><u>my </u></em><em><u>answer</u></em><em><u> </u></em><em><u>as </u></em><em><u>Brainlist</u></em><em><u> </u></em><em><u>you </u></em><em><u>would</u></em><em><u> </u></em><em><u>not </u></em><em><u>be </u></em><em><u>losing</u></em><em><u> </u></em><em><u>anything </u></em><em><u>and </u></em><em><u>about </u></em><em><u>your </u></em><em><u>answer</u></em><em><u> </u></em><em><u /></em><em><u> </u></em><em><u>do </u></em><em><u>yourself</u></em></h3>

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You want to minimize an objects thermal energy loss on a cold day. How does heat energy transfer affect thermal energy loss?
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Explanation:

Thermal energy loss has to do with loss of heat energy by a body to another body or its environment. The aim of the process is usually the attainment of thermal equilibrium between the body and its environment.

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6 0
3 years ago
How many Faradays of electricity are carried by 1.505×10^23 electronsk​
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Mole of electron required by 1.505 *10^{23} mole is 2.5* 10  ^{-1}

  • Faraday law expressed how the  change that is been being produced by a current at an electrode-electrolyte interface is related and  proportional to the quantity of electricity  that is been used.

  • There is one mole of electron required for 1 Faraday of electricity.

  • Avogadro constant is 6.02*10^{23}

  • Mole of electron can be calculated by dividing the number of electron by avogadro's constant.

=\frac{1.505*10^{23} }{6.02*10^{23} }

= 2.5* 10^{-1}  Faraday  of electricity

Therefore, it requires  2.5*10^{-1} Faraday of electricity for the 1.505 *  10^{23}  mole.

Learn more at: brainly.com/question/1640558?referrer=searchResults

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hope it helps..

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This isn't a good question but I guess!
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