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5 0

Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)

<h3>Strength of electrolytes</h3>

Strong electrolytes: are completely ionized in aqueous solution.
Weak electrolytes: are partially ionized in aqueous solution.

Let's consider the ionization of ammonium hydroxide, which is a weak base.

NH₄OH ⇄ NH₄⁺ + OH⁻

Why is it considered a weak base?

a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.

b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.

c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.

d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.

Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.

Learn more about weak bases here: brainly.com/question/322250

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Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it.

kakasveta [241]

Answer:

The volume will be 89.6875 ml

Explanation:

So to count this we will use a single proportion.

0.0640 mol - 1000 ml

5.74×10−3 mol - x ml

x ml=5.74×10−3 mol*1000 ml/0.0640 mol=89.6875 ml

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3 years ago

What is produced by a neutralization reaction between an arrhenius acid and an arrhenius base?

stepladder [879]

Answer: Salt and Water

Explanation:

An Arrhenius acid (HCl) can best be defined as any substance that when added to water increases the concentration of H+ ions.

While an Arrhenius base (KOH) is any substance that when added to water increases the concentration of OH- ions.

When an Arrhenius acid such as HCl reacts with an Arrhenius base such as KOH, the end products will be salt and water, in a process called Neutralization Reaction.

HCl (aq) + KOH (aq) -------> KCl (aq) + H2O (l)

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2 years ago

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th

MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

$\frac{K_1}{K_2}=?$