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laila [671]
2 years ago
15

PLS HELP ME NOW ASAP

Chemistry
1 answer:
Katyanochek1 [597]2 years ago
5 0

Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)

<h3>Strength of electrolytes</h3>
  • Strong electrolytes: are completely ionized in aqueous solution.
  • Weak electrolytes: are partially ionized in aqueous solution.

Let's consider the ionization of ammonium hydroxide, which is a weak base.

NH₄OH ⇄ NH₄⁺ + OH⁻

Why is it considered a weak base?

a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.

b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.

c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.

d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.

Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.

Learn more about weak bases here: brainly.com/question/322250

#SPJ1

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which atom has a change in oxidation number of -3 in the following redox reaction K2Cr2O7 + H2O +S --&gt; KOH + Cr2O3 +SO2
yaroslaw [1]
You have to calculate the oxidation estates of the atoms in each compound.

I will start with K2Cr2O7 because I believe that Cr is the best candidate to reduce its oxidation number in 3 units.

In K2Cr2O7:

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- O has oxidation state of 2*, then O7 has a charge of 7* (2-) = 14-.

That makes that Cr2 has charge of 14 - 2 = +12, so each Cr has +12/2 = +6 oxidation state.

In Cr2O3:

- O has oxidation state of 2-, then O3 has charge 3 * (2-) = - 6

- Then, Cr2 has charge 6+, and each Cr has charge 6+ / 2 = 3+.

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Answer: Cr has a change in oxidation number of - 3.
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3 years ago
What is the energy change if 84.0 g of calcium oxide (CaO) reacts with excess water in the following reaction?
pochemuha
   The energy change  if 84.0 g   of CaO  react  with  excess  water is  98KJ of heat is released.

calculation
heat  =  number of moles  x  delta H

delta H = - 65.2  Kj/mol

first find the number of  moles  of  CaO reacted

moles = mass/molar mass
the molar mass  of CaO =  40 +  16=  56 g/mol
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moles therefore = 84 g/56 g/mol =1.5 moles

Heat is therefore =  1.5 moles  x -65.2 = - 97.8 Kj = -98 Kj

  since  sign is  negative  the   energy  is released 

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