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Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)

<h3>Strength of electrolytes</h3>

Strong electrolytes: are completely ionized in aqueous solution.
Weak electrolytes: are partially ionized in aqueous solution.

Let's consider the ionization of ammonium hydroxide, which is a weak base.

NH₄OH ⇄ NH₄⁺ + OH⁻

Why is it considered a weak base?

a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.

b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.

c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.

d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.

Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.

Learn more about weak bases here: brainly.com/question/322250

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To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

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To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

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Which is related to the general line equation:

$y=mx+b$

Whereas:

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It means that we answer to the blanks as follows:

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