Freshwater biomes contain less salt than ocean biomes. true or false

An atom of oxygen (O) has 8 protons, 8 neutrons, and 8 electrons. What is its mass number?

Tema [17]

16 is the mass of an atom of Oxygen

5 0

3 years ago

What is the charge on an atom after it loses an electron during the formation of a bond?

NARA [144]

Answer:

One positive charge

Explanation:

In a neutral atom, the number of positive and negative particles are equal. This leaves the atom with a net charge of zero, 0.

When the number of protons in an atom is greater than the number of electrons, the atom becomes positively charged. When an atom loses an electron when a bond wants to form, it has a net positive charge.

The number of electrons lost or gained determines the charge.

7 0

3 years ago

Which of these substances are molecules?

Studentka2010 [4]

A molecule is an electrically neutral group of two or more atoms held together by chemical bonds. So I would say is all of them, as they all contain two atoms each even in the diatomics

7 0

3 years ago

Read 2 more answers

Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction

AVprozaik [17]

Answer:

The volume of the flask is 20.245 litres .

Explanation:

We are given with following information-

$PV=nRT$ -------- 1

where R = $0.0821L.atom/mole.K$

Molar mass of $PCl_5=208.22g/mole$

The given chemical equation is -

$2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5 _(_s_)$ --------- 2

Now , calculation -

Mass of $PCl_5$ formed = 118g

Molar mass of $PCl_5$ = $208.22g/mole$

Mole = $\frac{mass (g)}{molar mass}$

Therefore , moles of $PCl_5$ formed = $\frac{118}{208.22}$

From equation 2 , we get to know that ,

2mole $PCl_5$ formed from 5 mole $Cl_2 _(_g_)$

Therefore , $\frac{118}{208.22}$ mole $PCl_5$ formed from $\frac{5}{2} \times\frac{118}{208.22}$ mole $Cl_2 _(_g_)$

Moles of $Cl_2 _(_g_)$ used = $\frac{5\times118}{2\times208.22} mole$

R= $0.0821L.atom/mole.K$

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of $Cl_2 _(_g_)$ (n)= $\frac{5}{2} \times\frac{118}{208.22}$ moles

Applying the formula above in 1 equation , that is

PV = nRT

putting the given values -

$1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322$

V = 20.245 litres.

Hence , the volume of the flask is 20.245 litres .

8 0

3 years ago

) Calculate the molarity of a solution prepared by dissolving 117 g of sodium chloride (NaCl) in enough water to make 2.7 liters

Andrej [43]

The Molarity of the solution is given by:
$Molarity = \frac{moles-of-solute}{liters-of-solution}$ --- (A)

But NaCl, which is a solute, is given in grams.
Therefore, first, we need to convert grams into moles.

Molecular weight of NaCl = 58.44 grams/mole.

So,
117 grams * (moles/ 58.44 grams) = 2.00 moles of NaCl

Now that we have moles of NaCl, plug in the values in (A):
(A) => Molarity = (2 / 2.7 ) = 0.741 moles/litre

The correct answer is: 0.741 moles/litre = Molarity

8 0

3 years ago