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3 years ago

Why is Adam Driver hot? like I want him to step on me :)

Chemistry

1 answer:

3241004551 [841]3 years ago

5 0

Answer:

AWWWWWWWWWWWWWWWW SOOO NICEEE

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5. Why are the poppy seeds placed in different places (not together)?

Mademuasel [1]

In the atom model, the poppy seeds are placed in different places to represent the different position of electrons.

6 0

3 years ago

Read 2 more answers

Which of the gas laws takes into account the forces of attraction between molecules based on the characteristics of the gas? *

Alika [10]

The answer is Boyle’s Law

5 0

3 years ago

The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,

Masja [62]

Answer: The concentration of $Au^{3+}$ in the solution is $1.87\times 10^{-14}M$

Explanation:

The given cell is:

$Pt(s)|H_2(g.1atm)|H^+(aq.,1.0M)||Au^{3+}(aq,?M)|Au(s)$

Half reactions for the given cell follows:

Oxidation half reaction: $H_2(g)\rightarrow 2H^{+}(1.0M)+2e^-;E^o_{H^+/H_2}=0V$ ( × 3)

Reduction half reaction: $Au^{3+}(?M)+3e^-\rightarrow Au(s);E^o_{Au^{3+}/Au}=1.50V$ ( × 2)

Net reaction: $3H_2(s)+2Au^{3+}(?M)\rightarrow 6H^{+}(1.0M)+2Au(s)$

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.50-0=1.50V$

To calculate the concentration of ion for given EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^6}{[Au^{3+}]^2}$

where,

$E_{cell}$ = electrode potential of the cell = 1.23 V

$E^o_{cell}$ = standard electrode potential of the cell = +1.50 V

n = number of electrons exchanged = 6

$[Au^{3+}]=?M$

$[H^{+}]=1.0M$

Putting values in above equation, we get:

$1.23=1.50-\frac{0.059}{6}\times \log(\frac{(1.0)^6}{[Au^{3+}]^2})$

$[Au^{3+}]=1.87\times 10^{-14}M$

Hence, the concentration of $Au^{3+}$ in the solution is $1.87\times 10^{-14}M$

7 0

3 years ago

Compare and contrast diffusion and osmosis. Include at least one similarity and one difference between the two processes.

Softa [21]

Osmosis is the diffusion of water across a semipermeable membrane (usually cell membrane) from a region of low solute concentration to a more concentrated solution so it can reach equilibrium (balance).

Diffusion is a spontaneous movement of particles from an area of high concentration to an area of low concentration.

Both results in particles moving and help balance out the concentrations.
Also, in osmosis, the water molecules are moving. In diffusion, it is the solutes moving.

I hope this helps and explains well.

4 0

3 years ago

Identify the factors that govern the speed and direction of a reaction. Check all that apply.

Fiesta28 [93]

Answer: option B and option C

Explanation:

4 0

3 years ago