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Andru [333]
3 years ago
8

Click in the answer box to activate the palette. Use the half-reaction method to balance the following equation in acidic soluti

on. It is not necessary to include any phases of matter for any species. CN− + MnO4− → CNO− + MnO2
Chemistry
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

The balanced reaction in the acidic medium is:

2MnO4^-+3CN^-+2H^+\rightarrow 2MnO_2+H_2O+3CNO^-

Explanation:

CN^- + MnO4^-\rightarrow CNO^- + MnO_2

1) CN^-\rightarrow CNO^- ( oxidation)

Balance oxygen by adding water :

CN^-+H_2O\rightarrow CNO^-

Now , balance hydrogen by adding hydrogen ions on the side where hydrogen are less.

CN^-+H_2O\rightarrow CNO^-+2H^+

Add electrons to balance charge where positive charge is more.

CN^-+H_2O\rightarrow CNO^-+2H^++2e^-..[1]

2) MnO4^-\rightarrow MnO_2 (reduction)

Balance oxygen by adding water :

MnO4^-\rightarrow MnO_2+2H_2O

Now , balance hydrogen by adding hydrogen ions by adding them on the side where hydrogen are less.

MnO4^-+4H^+\rightarrow MnO_2+2H_2O..[2]

Add electrons to balance charge where positive charge is more.

MnO4^-+4H^++3e^-\rightarrow MnO_2+2H_2O..[2]

3 × [1] + 2 × [2]

The balanced reaction in the acidic medium is:

2MnO4^-+3CN^-+2H^+\rightarrow 2MnO_2+H_2O+3CNO^-

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Answer:

Percent error = 12.5%

Explanation:

In a measurement you can find percent error following the formula:

Percent error = |Measured value - Accepted Value| / Acepted value * 100

Based on the data of the problem, accepted value is 22.4L and the measured Value (Value of Sara) was 19.6L.

Replacing:

Percent error = |Measured value - Accepted Value| / Acepted value * 100

Percent error = |19.6L - 22.4L| / 22.4L * 100

Percent error = |-2.8L| / 22.4L * 100

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3 0
3 years ago
Examine the reaction equation. Mg(OH)2(s) + HCl(aq) →H2O(l) + MgCl2(aq) What coefficients will balance the equation? A) 2, 4, 2,
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Answer:

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6 0
3 years ago
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Concentrated hydrochloric acid is made by pumping hydrogen chloride gas into distilled water. If concentrated HCl contains 439 g
Elza [17]

Answer:

12.10 mol / 1 L

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),  

n = moles of solute ( unit = mol ),  

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .  

From the question ,

The data given is as follows -

w = 439 g

As , we known for HCl ,

m = 36.46 g/mol

V = 1 L

From the above data ,

Moles are given as -

n = w / m

n = 439 / 36.26 = 12.10 mol ,

Now , the molarity is given as ,

M = n / V

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7 0
3 years ago
How many moles of silver nitrate (AgNO3) are needed to produce 6.75 moles of copper (ll) nitrate (Cu(NO3)2) upon reacting with e
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Answer:

13.5 moles of AgNO₃

Explanation:

To determine the reaction:

Reactants: AgNO₃ and Cu

Products: Cu(NO₃)₂ and Ag

2 moles of AgNO₃ react to 1 mol of Cu, in order to produce 1 mol of Cu(NO₃)₂ and 2 moles of solid silver.

2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag

Our production was 6.75 moles of Cu(NO₃)₂

Let's make the rule of three:

1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃

Then, our 6.75 moles were definetely produced by (6.75 . 2) /1 = 13.5 moles.

If the copper was in excess, then the silver nitrate is the limiting reactant:

2 mol of AgNO₃ can produce 1 mol of Cu(NO₃)₂

Then, 13.75 moles of silver nitrate must produce (13.5 . 1) /2 = 6.75 moles of Cu(NO₃)₂

6 0
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