11) How many moles of CO2 can be produced from 5.0 moles of O2?

Chiara knows that weight is affected by gravitational pull. She is putting together a poster to display in her classroom.

Tanya [424]

Answer: A

Explanation: 150 lb * 1/6 = 25 lb

8 0

2 years ago

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How many grams of aluminum are required to react with 35 mL of 2.0 M hydrochloric acid, HCl?__ HCl + __ Al --> __ AlCl3 + __

kiruha [24]

Answer:

0.6258 g

Explanation:

To determine the number grams of aluminum in the above reaction;

determine the number of moles of HCl
determine the mole ratio,
use the mole ratio to calculate the number of moles of aluminum.
use RFM of Aluminum to determine the grams required.

Moles of HCl

35 mL of 2.0 M HCl

2 moles of HCl is contained in 1000 mL

x moles of HCl is contained in 35 mL

$x \: mol \: = \: \frac{2 \: \times \: 35}{1000} \\ = 0.07 \: moles \:$

We have 0.07 moles of HCl.

Mole ratio

Balanced equation

6HCl(aq) + 2Al(s) --> 2AlCl3(aq) + 3H2(g)

Hence mole ratio = 6 : 2 (HCl : Al

but moles of HCl is 0.07, therefore the moles of Al;

$= \frac{2}{6} \times 0.07 \\ \: = 0.0233333 \: moles$

Therefore we have 0.0233333 moles of aluminum.

Grams of Aluminum

We use the formula;

$grams \: = moles \: \times \: rfm$

The RFM (Relative formula mass) of aluminum is 26.982g/mol.

Substitute values into the formula;

$= 0.0233333 \: moles \: \times \: 26.982 \: \frac{g}{mol} \\ = 0.625799 \: grams$

The number of grams of aluminum required to react with HCl is 0.6258 g.

3 0

1 year ago

What is the molecular formula of an empirical N2H3 if n=2? SHOW WORK!

aliya0001 [1]

A compound's empirical formula tells you what the smallest whole number ratio between the atoms that make up that compound is.

I think of the empirical formula as a building block for molecules. A compound's molecular formula will depend on how many building blocks are needed to build a molecule of a given substance.

In your example, you know that the empirical formula of the compound is

NO

2

.

This tells you that the minimum ratio between nitrogen atoms and oxygen atoms is

1

:

2

. In other words, the molecular formula will be a multiple of this building block.

molecular formula

=

empirical formula

×

n

, where

n

- the number of building blocks needed to build the molecular formula.

You also know that the molar mass of your compound is

92 g/mol

.

This means that the molar mass of all the atoms that make up that molecule must add up to give

92 g/mol

.

So, how would you determine how many building blocks you need? Well, start by figuring out the molar mass of one building block, i.e. the molar mass of the empirical formula.

Since it contains one nitrogen atom and two oxygen atoms, you will get

1

×

14.0067 g/mol

+

2

×

15.9994 g/mol

=

46.0055 g/mol

So, if one building block has a molar mass of

46.0055 g/mol

, how many would you need to get the molecule?

46.0055 g/mol

⋅

n

=

92 g/mol

n

=

92

g/mol

46.0055

g/mol

=

1.99976

≈

2

This means that the compound's molecular formula, which lists all the atoms that make up a molecule, will be

(

NO

2

)

×

2

=

N

2

O

4

→

dinitrogen tetroxide

7 0

2 years ago

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Molarity of 2%W/V of NaOH is

TiliK225 [7]

Assume it is 1 litre and weighs 1kg.
2 percent of 1 kg is 20g.
20g divided by molar mass of NaOH.
20g divide by 40 = 0.5 mole
0.5 mole in a litre would be 0.5M
That is the answer: 0.5M

6 0

2 years ago

You have 0.14 moles of sodium chloride (NaCl). How many grams do you have? ( 1 mole of NaCl = 58 grams NaCl) *

Step2247 [10]

Answer:

Option D is correct = 8.12 grams of NaCl

Explanation:

Given data:

Moles of sodium chloride = 0.14 mol

Mass of sodium chloride = ?

Solution:

Formula:

Number of moles = mass of NaCl / Molar mass of NaCl

Molar mass of NaCl = 58 g/mol

Now we will put the values in formula.

0.14 mol = Mass of NaCl / 58 g/mol

Mass of NaCl = 0.14 mol × 58 g/mol

Mass of NaCl = 8.12 g of NaCl

Thus, 0.14 moles of NaCl contain 8.12 g of NaCl.

4 0

3 years ago