You need to find the moles of CaCl, you can either do a grams to mol conversion, OR, you can do the equation used in A without the last step which was converting it into the grams on CaCl. You get .00848146 mol CaCl. with that you can find the concentration using the molarity equation which is M=mol/L. M=.000848146mol/3.98 L. M=0.000213 or your teacher may want you to write it 0.000213 M CaCl. Hope I helped :)
Answer:
Explanation:
Mole = No. Of atom/Avogadro const
Avogadro constant= 6.02×10^23
Mass of Cu =22g
Molar mass of Cu =63.5g/mol
Mole = mass/molar mass
Mole = 22/63.5
Mole = 0.346
No. Of atom=mloe ×avogadro conts
No. Of atom = 0.346 × 6.02×10^23
No. Of atom = 2.09 × 10^23atoms
The complete reaction for potassium hydroxide (KOH) and phosphoric acid (H3PO4) would yield products of water (H2O) and potassium phosphate (K3PO4).
3 KOH + H3PO4 ---> K3PO4 + 3 H2O
The net ionic equation would be obtained when you express the compounds in their ionic forms and eliminating the spectator ions. Spectator ions are the ions that appear in the reactant and product side. They do not actively participate the in the reaction.
3 K+ + 3 OH- + H3PO4 ---> 3K+ + PO4^3- + 3 H2O
H3PO4 is a weak acid so it does not dissociate. H2O is not an ionic compound so it also does not dissociate. Therefore, the spectator ion is the potassium ion K+. The net ionic reaction is
3 OH- + 3 H3PO4 ---> PO4^3- + 3 H2O
Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
The London dispersion force (intermolecular force) <span>is a temporary attractive </span>force between molecules.