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Tanya [424]
3 years ago
6

What is the ratio 15 to 35 written as a fraction in lowest terms?

Mathematics
2 answers:
Sphinxa [80]3 years ago
7 0
15/35
3/7 the answer is 3/7 which is written in the lowest terms
Elden [556K]3 years ago
3 0
15/35
3/7.................
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How will the graph of g(x) = 8x-1 differ from the graph of f(x) = 8x ?
exis [7]
The graph of y =8x goes through the origin (0,0) the graph of Y = 8x-1 is displaced on the negative y -axis and goes through the point (0, -1)
3 0
3 years ago
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Find the distance of the line segment joining the two points (-4 /2 - /12) and (/32, 2/3)
astraxan [27]

Answer: 4\sqrt{3} .

Step-by-step explanation:

Distance formula : Distance between points (a,b) and (c,d) is given by :-

D=\sqrt{(d-b)^2+(b-a)^2}

Distance between points (-4\sqrt{2},\sqrt{12}) \text{ and }(-\sqrt{32}, 2\sqrt{3}).

D=\sqrt{(2\sqrt{3}-(-\sqrt{12}))^2+(-\sqrt{32}-(-4\sqrt{2}))}\\\\=\sqrt{(2\sqrt{3}+\sqrt{2\times2\times3})^2+(-\sqrt{4\times4\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}-\sqrt{2^2\times3})^2+(-\sqrt{4^2\times2}+4\sqrt{2})^2}\\\\=\sqrt{(2\sqrt{3}+2\sqrt{3})^2+(-4\sqrt{2}+4\sqrt{2})^2}\\\\=\sqrt{(4\sqrt{3})^2+0}\\\\=4\sqrt{3}\text{ units}

Hence, the correct option is 4\sqrt{3} .

3 0
3 years ago
Is 7766 a even number ?
fiasKO [112]

Answer: Yes.

Step-by-step explanation: If a number ends in 0, 2, 4, 6, or 8, the number even number.

6 0
3 years ago
How many times greater is the value of the 4 in 640,700 than the value of the 4 in 67,040
Dafna1 [17]
640,700 :- the four in this number is 40,000
67,040 :- the four in this number is 40

Now, we need to find out how many times greater 40,000 is than 40.

40,000/40 = 1000

Answer: It is 1000 times greater. 
6 0
3 years ago
Read 2 more answers
Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
2 years ago
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