The answer for this question is 0
Hello:
x^5 – x^4 + x^2 =x^2(x^3 - x^2 +1)
(u/v)(x)= x^2(x^3 - x^2 +1)/(-x^2)
(u/v)(x)= - (x^3 - x^2 +1) = -x^3+x^2-1 ( x : no zero)
Answer:
22 times with 1 as the remainder.
Step-by-step explanation:
Answer:
Option C - Simplify the right side using the "difference of two logs is the log of the quotient" property.
Step-by-step explanation:
Given : Expression ![\ln (x-1)=\ln 6-\ln x](https://tex.z-dn.net/?f=%5Cln%20%28x-1%29%3D%5Cln%206-%5Cln%20x)
To find : What is the first step in solving the expression ?
Solution :
Expression ![\ln (x-1)=\ln 6-\ln x](https://tex.z-dn.net/?f=%5Cln%20%28x-1%29%3D%5Cln%206-%5Cln%20x)
Step 1 - Simplify the right side using the "difference of two logs is the log of the quotient" property.
i.e. ![\ln a-\ln b=\ln(\frac{a}{b})](https://tex.z-dn.net/?f=%5Cln%20a-%5Cln%20b%3D%5Cln%28%5Cfrac%7Ba%7D%7Bb%7D%29)
Apply the first step we get,
![\ln (x-1)=\ln(\frac{6}{x})](https://tex.z-dn.net/?f=%5Cln%20%28x-1%29%3D%5Cln%28%5Cfrac%7B6%7D%7Bx%7D%29)
Therefore, Option C is correct.
Answer:
.
Step-by-step explanation:
We are given that
and
(because that's the ground), so substituting that into
gives
.