Ask question

Ask question

All categories

schepotkina [342]

3 years ago

10

I really need help i’m in a really big rush

1 answer:

kompoz [17]3 years ago

3 0

1. The speed is at a constant rate same with the acceleration and velocity

2. When there getting close to the top there speed, acceleration, and velocity all start to decrease

3. The speed and acceleration and velocity all on the way down drastically increase number

hope I helped

You might be interested in

Boyle’s Law states that when a sample of gas is compressed at a constant temperature, the pressure P of the gas is inversely pro

jolli1 [7]

Answer:

a) $V=\dfrac{5.3}{P}$

b) $ML^{-4}T^{-2}$ .

Explanation:

Given that

Boyle's law

P V = Constant ,at constant temperature

a)

Given that

$P_1=50KPa$

$V_1=0.106m^3$

We know that for PV=C

$P_1V_1=P_2V_2=PV$

Now by putting the values

PV= 50 x 0.106

$V=\dfrac{5.3}{P}$

Where P is in KPa and V is in $m^3$

b)

PV= C

Take ln both sides

So $\ln(PV)=\ln C$

lnP + lnV =lnC ( C is constant)

By differentiating

$\dfrac{dP}{P}+\dfrac{dV}{V}=0$

So

$\dfrac{dP}{dV}=-\dfrac{P}{V}$

When P= 50 KPa

$\dfrac{dP}{dV}=-\dfrac{50}{V}\ \dfrac{KPa}{m^3}$

It indicates the slope of PV=C curve.

It unit is $\dfrac{Pa}{m^3}$ .

Or we can say that $ML^{-4}T^{-2}$ .

5 0

3 years ago

Read 2 more answers

One end of a metal rod is in contact with a thermal reservoir at 699. K, and the other end is in contact with a thermal reservoi

bulgar [2K]

Answer:

a)ΔS₁ = - 9.9 J/K

ΔS₂ = 69 J/K

b)The entropy change for the rod = 0 J/K

c)ΔS = 59.1 J/K

Explanation:

Given that

T₁ = 699 K

T₂= 101 K

Q= 6970 J

Change in entropy given as

$\Delta S=\dfrac{Q}{T}$

For 699 K:

$\Delta S_1=\dfrac{Q}{T}$

$\Delta S_1=-\dfrac{6970}{699}$

ΔS₁ = - 9.9 J/K ( Negative because heat is leaving from the system)

For 101 K;

$\Delta S_2=\dfrac{Q}{T}$

$\Delta S_2=\dfrac{6970}{101}$

ΔS₂ = 69 J/K

The entropy change for the rod = 0 J/K

Entropy change for the system

ΔS = ΔS₂ + ΔS₁

ΔS = 69 -9.9 J/K

ΔS = 59.1 J/K

8 0

3 years ago

When a battery, a resistor, a switch, and an inductor form a circuit and the switch is closed, the inductor acts to oppose the c

vladimir1956 [14]

Answer:Time constant gets doubled

Explanation:

Given

L-R circuit is given and suppose R and L is the resistance and inductance of the circuit then current is given by

$i=i_0\left [ 1-e^{-\frac{t}{\tau }}\right ]$

where $i_0$ is maximum current

i=current at any time

$\tau =\frac{L}{R}=time\ constant$

$\tau '=\frac{2L}{R}=2\tau$

thus if inductance is doubled then time constant also gets doubled or twice to its original value.

5 0

4 years ago

- A sports car travels at 180km/h. Calculate and write the steps to show how long will it travel in 40

Dmitriy789 [7]

Answer:

20 km

Explanation:

20 km

6 0

3 years ago

The mass of the man is 86kg. What is the force of friction that slowed him down?

Bumek [7]

Answer:

Is it gravity????????

4 0

4 years ago

Read 2 more answers