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galben [10]
3 years ago
6

A large semi-truck is moving a house from one lot to another. The amount of force required to move the house 15.A horizontally a

distance of 72 meters is 3.500 pewtens How much work will be done ce the house?
Physics
1 answer:
dlinn [17]3 years ago
5 0

Answer:

252J

Explanation:

Given parameters:

Distance  = 72m

Force  = 3.5N

Unknown:

Work done on the house  = ?

Solution:

Work done is the force applied to move a body through a particular distance.

    Work done  = Force x distance

Now insert the parameters and solve;

   Work done  = 3.5 x 72  = 252J

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A car (mass = 1090 kg) is traveling at 30.4 m/s when it collides head-on with a sport utility vehicle (mass = 2880 kg) traveling
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Two containers (A and B) are in thermal contact with an environment at temperature T = 280 K. The two containers are connected b
zmey [24]

Answer:

The maximum amount of work is  W = 1563.289 \ J

Explanation:

From  the question we are told that

   The temperature of the environment is  T = 280\ K

    The volume of container A is  V_A = 2 m^3

    Initially the number of moles  is  n = 1.2 \ moles

     The volume of container B is V_B = 3.5 \ m^3

     

At equilibrium of the gas the maximum work that can be done on the turbine is mathematically represented as

             W =  P_A V_A  ln[ \frac{V_B}{V_A} ]

Now from the Ideal gas law

          P_A V_A =  nRT

So substituting for P_A V_A in the equation above

          W =  nRT ln [\frac{V_B}{V_A} ]

Where R is the gas constant with a values of  R =  8.314 \  J/mol

Substituting values we have that

            W = 1.2 * (8.314) * (280) * ln [\frac{3.5}{2} ]

          W = 1563.289 \ J

8 0
3 years ago
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