Answer:
left hand: 133 N upward
right hand: 83N downward
Explanation:
10 cm = 0.1m
Let g = 10m/s2. The pole gravity force would be 
. Suppose the pole mass distribution is uniform, this means the center of mass is at its geometric center, aka 5/2 = 2.5m from the top end.
In order for the system to stay balanced, the total net force and net moment must be 0
where 
are the forces exerted by his left and right hand, respectively.
We will pick his right hand (0.1 m from the top end) as moment pivot point. The total moment generated by pole gravity and his left hand must be 0
Distance (or moment arm length) from pole center to his right hand is 
Moment generated by gravity around his right hand is: 
counter-clockwise
Distance (or moment arm length) from left hand to his right hand is 
Moment generated by force from his left hand around his right hand is: 
clockwise
Since the total moment must be 0, the clockwised-direction moment = counterclockwised-direction moment:
upward
Therefore, the force exerted by his right hand must be 50 – 133 = -83 N or 83N downward
The crust since it is the outermost layer. Both the cores and the mantle are underground and are involved in very high temperatures. Answer is the crust
250 kg*m/s
Momentum is found by multiplying mass by velocity
25*10=250
Answer:
Kinetic energy = 44.1 J
Explanation:
Given:
Velocity of ball = 14 m/s
Mass of ball = 0.45 kg
Find:
Kinetic energy
Computation:
An item's kinetic energy is force it has as a result of its motion. It is the amount of work necessary to move a body of a known volume from rest to a specified velocity.
Ke = (1/2)(m)(v²)
Ke = (1/2)(0.45)(14²)
Ke = (1/2)(0.45)(196)
Kinetic energy = 44.1 J
