Answer:
a)the process by which heat or electricity is directly transmitted through the material of a substance when there is a difference of temperature
b)the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat
c)radiation is the emission or transmission of energy in the form of waves or particles through space or through a material medium.
Answer:
The optimum length of the antenna is 2.27 m
Explanation:
Given:
Broadcasting frequency Hz
From the formula of wavelength in terms of frequency,
Where speed of light
m
For finding the length of antenna,
m
Therefore, the optimum length of the antenna is 2.27 m
Answer:
1. The image is real
2. 5.85
3. h' = 3.05 mm
4. The image is upright
Explanation:
1. Start with the first lens and apply 1/f = 1/p + 1/q
1/5.01 = 1/13.7 + 1/q
q = 7.90 cm
Since that distance is behind the first lens, and the second lens is 62.5 cm behind the first lens, that distance is 62.5 - 7.90 = 54.6 cm in front of the second lens, and becomes the object for that lens, thus,
1/25.9 = 1/54.6 + 1/q
q = 49.3 cm behind the second lens
Using that information, since q is positive, the image is real
2. Also, using that information, you have the second answer, which is 49.3 cm
The height can be found from the two magnifications.
m = -q/p
m1 = -7.9/13.7 = -.577
m2 = -49.3/54.6 = -.903
Net m = (-.577)(-.903) = .521
Then, m = h'/h
.521 = h'/5.85
3. h' = 3.05 mm
4. For the fourth answer, since the overall magnification is positive, the final image is upright
The choice c. 100 cm / s²
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I hope I helped you^_^