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Genrish500 [490]
3 years ago
14

When a battery, a resistor, a switch, and an inductor form a circuit and the switch is closed, the inductor acts to oppose the c

hange in the current.
How is the time constant of the circuit affected by doubling the resistance in the circuit?
Physics
1 answer:
vladimir1956 [14]3 years ago
5 0

Answer:Time constant gets doubled

Explanation:

Given

L-R circuit is given and suppose R and L is the resistance and inductance of the circuit then current is given by

i=i_0\left [ 1-e^{-\frac{t}{\tau }}\right ]

where i_0 is maximum current

i=current at any time

\tau =\frac{L}{R}=time\ constant

\tau '=\frac{2L}{R}=2\tau

thus if inductance is doubled then time constant also gets doubled or twice to its original value.                                      

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You are on an interstellar mission from the Earth to the 8,7 light-years distant star Sirius. Your spaceship can travel with 70%
marishachu [46]

Answer:

Time = 12.43 years

Mass = 4.71.43kg

Explanation:

Given the following :

Distance = 8.7 light years

Speed = 70% the speed of light

Diameter = 6m

Lengtg = 25m

Density = 1 hydrogen atom/m^3

Mass of proton(Me) = 1.673x 10^-27

A.) time it takes your spaceship to reach Sirius :

From the relation: Speed = (distance / time)

Time = distance / speed

Time = (70/100) × 1 light year

Distance = 8.7 light years

Time = 8.7 / 0.7 = 12.4285 years

Time = 12.43 years

B.) Mass of inter-stellar gas that collides with the spaceship can be calcuted by finding the product of the surface area of the cylindrical space ship and the mass of proton.

That is ;

surface area * mass of proton

Surface area of a cylinder = 2πrh + πr^2×Me

= 2πrh + Me×πr^2)

=( 2 × 22/7 × 3 × 25) + (22/7 × 3^2 × 1.673 * 10^-27)

= 2× 235.714 + 28.285) × 1.673 * 10^-27

= 471.428 + 47.31 * 10^-27

= 471.428 + 4.73 × 10^-26

= 4.71.43kg approximately

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2 years ago
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How much kinetic energy does an object have that is moving at a rate of 30 m/s and has a mass of 4000 kg ?
DaniilM [7]

Answer:

K = 1800 kJ

Explanation:

Given that,

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K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 4000\times 30^2\\\\K=1800000\\\\or\\\\K=1800\ kJ

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