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kondaur [170]
3 years ago
11

What’s the answer to this math question

Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

The answer would probably be c

Step-by-step explanation:

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Use elimination to solve the system of equations.<br><br> 3x – 5y = –9<br> x + 2y = 8
nalin [4]

Answer:

x=2

y=3

Step-by-step explanation:

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PLEASE HELP DUE TONIGHT! 100 PTS
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Answer:

a. $15.00

b. $15.00

c. they earn the same. If you divide Carl's hours by the amount of time he works, for instance, 45÷3=15, you get 15 for all of them. They earn the same.

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Point C is the midpoint of a segment AB . What are the coordinates of point B, if: A(–1, 3), C( 1, –1)
a_sh-v [17]

Answer:

(3,-5)

Step-by-step explanation:

To find the x coordinate of the  midpoint, add the  x coordinates together and divide by 2

The x coordinate is

(x1+x2)/2

We know one point and the midpoint

( -1+x)/2 = 1

Multiply by 2

-1 +x = 2

Add 1

x =2+1

x=3

To find the y coordinate of the midpoint, add the  y coordinates together and divide by 2

The y coordinate is

(y1+y2)/2

We know one point and the midpoint

(3+y)/2 = -1

Multiply by 2

3+y = -2

Subtract 3

y = -2-3

y =-5

The other endpoint is (3,-5)

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Ursula surveyed 50 classmates about their favorite ice cream flavors. Each classmate chose one flavor. The results are shown in
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We need the circle graph.

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5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
4 years ago
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