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lord [1]
4 years ago
11

Its a PEMDAS question folks i hope you can help

Mathematics
2 answers:
motikmotik4 years ago
8 0

the answer would be c

V125BC [204]4 years ago
4 0

You need to understand PEMDAS, not just memorize it, to use it correctly.

P - first, do parentheses

E - next, do exponents

The first two are done one at a time in that order. Now we get to MDAS. Here we have two groups of operations. The first group is MD, multiplications and divisions.

MD - then do multiplications and divisions, from left to right, in the order they appear

The second group is additions and subtractions.

AS - finally, do additions and subtractions, from left to right, in the order they appear.

Now let's look at your problem and follow PEMDAS correctly.

19 + 14 \div 10 \cdot 4 - 24 =

P - there are no parentheses.

E - there are no exponents.

MD - now we do multiplications and divisions, from left to right, in the order they appear. Do one operation at a time per line, so you don't forget to do any operation.

We start with the division 14/10:

= 19 + 1.4 \cdot 4 - 24

Now we have a multiplication, so we do the multiplication 1.4 * 4.

= 19 + 5.6 - 24

All multiplications and divisions are done. Now we move on to the step AS. We do additions and subtractions from left to right. We start with the addition 19 + 5.6.

= 24.6 - 24

Finally, we have a single operation left to do. We do the subtraction 24.6 - 24.

= 0.6

Answer: C 0.6

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Simplification <br>-4a+b+3c+3a-3b+c​
damaskus [11]

Answer:

-a+-2b+4c

Step-by-step explanation:

Combine like terms

-4a+ 3a= -a

b+ -3b= -2b

3c+ c= 4c

7 0
3 years ago
A veterinarian’s assistant made a table that shows the animals seen in the office in one week. What is the probability that the
horsena [70]

Answer:

The probability that the pet seen was sick is 53.57%.

Step-by-step explanation:

The probability of an event <em>E</em> is the ration of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Here,

n (E) = number of favorable outcomes

N = total number of outcomes

Denote the events as follows:

<em>C</em> = the pet is a cat

<em>D</em> = the pet is a dog

<em>O </em>=<em> </em>the pet is some other animal

<em>S</em> = the pet is sick.

The data provided is summarized as follows:

n (C) = 28

n (C ∩ S) = 3

n (D) = 42

n (B ∩ S) = 4

n (O) = 24

n (O ∩ S) = 8

Compute the probability that a cat was sick as follows:

P(C\cap S)=\frac{n(C\cap S)}{n(C)}=\frac{3}{28}

Compute the probability that a dog was sick as follows:

P(D\cap S)=\frac{n(D\cap S)}{n(D)}=\frac{4}{42}=\frac{2}{21}

Compute the probability that another animal was sick as follows:

P(O\cap S)=\frac{n(O\cap S)}{n(O)}=\frac{8}{24}=\frac{1}{3}

Compute the probability that the pet seen was sick as follows:

P (S) = P (C ∩ S) + P (D ∩ S) + P (O ∩ S)

       =\frac{3}{28}+\frac{2}{21}+\frac{1}{3}\\=\frac{9+8+28}{84}\\=\frac{45}{84}\\=0.5357

Thus, the probability that the pet seen was sick is 53.57%.

8 0
3 years ago
Read 2 more answers
Round 862 liters<br> to the nearest 10<br> liters.
Maksim231197 [3]
The answer is 860 liters. You round down to 860 because it’s closer than 870.
5 0
2 years ago
There are 6 students. 2 of them are chosen for the position of president and Vice President. How many ways do we have to choose
Nutka1998 [239]

We have 15 ways to chose 2 students for the position of president and Vice President

<em><u>Solution:</u></em>

Given that,

There are 6 students. 2 of them are chosen for the position of president and Vice President.

<em><u>To find: number of ways we have to choose the students from the 6 students</u></em>

So now we have 6 students, out of which we have to choose 2 students

As we just have to select the students. We can use combinations here.

In combinations, to pick "r" items from "n" items, there will be ^{\mathrm{n}} \mathrm{C}_{\mathrm{r}} ways

^{\mathrm{n}} \mathrm{C}_{\mathrm{r}}=\frac{n !}{(n-r) ! r !}

<em><u>Then, here we have to pick 2 out of 6:</u></em>

Total students = n = 6

students to be selected = r = 2

\begin{aligned} 6 C_{2} &=\frac{6 !}{(6-2) ! 2 !} \\\\ 6 C_{2} &=\frac{6 !}{4 ! 2 !} \\\\ 6 C_{2} &=\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{4 \times 3 \times 2 \times 1 \times 2 \times 1} \\\\ 6 C_{2} &=15 \end{aligned}

Thus we have 15 ways to chose 2 students for the position of president and Vice President

3 0
3 years ago
Alisa had 1/2 a liter of juice in a bottle.She drank 3/4 of the juice that was in the bottle.How many liters of juice did she dr
Alik [6]
Started with .5 liters
She drank 3/4 of .5 liters
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375 Milliliters 
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