There are 12 peaches and 8 bananas in a fruit basket. You get a snack for yourself and three of your friends by choosing of the
1 answer:
Answer:
10.2% chance
Step-by-step explanation:
There are 12 peaches and 8 bananas for a total of 20 pieces of fruit.
So we can write it:
=
= .102 or 10.2% chance
For ease multiply all numerators (top numbers) together, then multiply the denominators (bottom numbers) together, and then divide.
12 * 11 * 10 * 9 = 11880
20 * 19 * 18 * 17 = 116,280
We start with 12 peaches and 20 total fruit, as we select a peach the number of peaches and total fruit goes down by one. We do this 4 times because you draw 4 fruits. If you select 1 fruit your chances of it being a peach are 12/20, each time you select a fruit the chances of it being a peach go down because you have 1 less total fruit, and 1 less peach. This is why you multiply each probability together.
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Answer:
Step-by-step explanation:
This is much faster than doing long-polynomial division, which we could have done, since the divisor is not in the form of <em>x</em><em> </em><em>-</em><em> </em><em>c,</em><em> </em>where<em> </em><em>−</em><em>c</em><em> </em>gives gives the OPPOSITE TERMS OF WHAT THEY REALLY ARE.
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Answer:
1. There is not enough evidence to support the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.
2. The test statistic is t.
Step-by-step explanation:
<em>The question is incomplete:</em>
- <em>Test the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.</em>
- <em>Which of the following is the test statistic for the appropriate test to determine if men who are distance runners live significantly longer, on average, than men who are not distance runners?</em>
The test statistic is t, as this is a t-test for the difference of means.
The claim is that men who were distance runners lived, on average, five years longer than those who were not distance runners.
Then, the null and alternative hypothesis are:
H_0: \mu_1-\mu_2=5\\\\H_a:\mu_1-\mu_2> 5
The significance level is 0.05.
The sample 1, of size n1=50 has a mean of 84.2 and a standard deviation of 10.2.
The sample 1, of size n1=30 has a mean of 79.2 and a standard deviation of 6.8.
The difference between sample means is Md=5.
The estimated standard error of the difference between means is computed using the formula:
Then, we can calculate the t-statistic as:
The degrees of freedom for this test are:
This test is a right-tailed test, with 78 degrees of freedom and t=0, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.5) is bigger than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that men who were distance runners lived, on average, five years longer than those who were not distance runners.