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grin007 [14]
3 years ago
9

Determine the enthalpy change of the following reaction: CO + H2O -> H2 + CO2

Chemistry
2 answers:
Tomtit [17]3 years ago
8 0

I think A is correct:

deltaH=(Enthalpie of reactents)-(Enthalpie of products)=110.525+285.5-393.5=2.525~2.825

Paraphin [41]3 years ago
7 0

Answer:

A. The enthalpy change for the reaction is 2.825 kJ

Explanation:

The given reaction is:

CO + H2O → H2 + CO2

The enthalpy change for a reaction is given as:

\Delta H = \sum n(p)\Delta H_{f}^{0}(products)-\sum n(r)\Delta H_{f}^{0}(reactants)

where np and nr are the number of moles of products and reactants

ΔH⁰f are the standard enthalpies of formation of the respective reactants and products

\Delta H = [1\Delta H_{f}^{0}(H2)+1\Delta H_{f}^{0}(CO2)]-[1\Delta H_{f}^{0}(CO)+1\Delta H_{f}^{0}(H2O)]

Substituting the given enthalpy data:

ΔH = [1(0) + 1(-393.5)] - [1(-110.525) + 1(-285.8)] = 2.825 kJ

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As discussed in class, the Fischer esterification reactants and products are at equilibrium. How was the equilibrium of the reac
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Answer:

See explanation

Explanation:

The particular reactants in the Fischer esterification reaction were not stated.

Generally, a Fischer esterification is a reaction that proceeds as follows;

RCOOH + R'OH ⇄RCOOR' + H2O

This reaction occurs in the presence of an acid catalyst.

We can shift the equilibrium of this reaction towards the products side in two ways;

I) use of a large excess of either of the reactants

ii) removal of one of the products as it is formed.

Any of these methods shifts the equilibrium of the Fischer esterification reaction towards the products side.

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3 years ago
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Answer:

3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C

Explanation:

One colligative property is the freezing point depression due the addition of a solute. The equation is:

ΔT=Kf*m*i

<em>Where ΔT is change in temperature = 0.400°C</em>

<em>Kf is freezing point constant of the solvent = 1.86°C/m</em>

<em>m is molality of the solution (Moles of solute / kg of solvent)</em>

<em>And i is Van't Hoff constant (1 for a nonelectrolyte)</em>

Replacing:

0.400°C =1.86°C/m*m*1

0.400°C / 1.86°C/m*1 = 0.215m

As mass of solvent is 280.0g = 0.2800kg, the moles of the solute are:

0.2800kg * (0.215moles / 1kg) = 0.0602 moles of solute must be added.

The mass of ethylene glycol must be added is:

0.0602 moles * (62.10g / mol) =

3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C

<em />

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3 years ago
Water molecules have a polarity, which allows them to be electrically attracted to other water molecules and other polar molecul
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<h3>Explanation:</h3>

                     Hydrogen Bond Interactions are those interactions which are formed between a <em>partial +ive</em> hydrogen atom bonded directly to most electronegative atoms (i.e. Fluorine, Oxygen and Nitrogen) of one molecule interacts with the <em>partial -ive</em> most electronegative atom of another molecule. These interactions are considered the strongest intermolecular interactions and are responsible for many stronger physical properties of water like, boiling point, viscosity, solubility e.t.c.

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What is the number of electrons shared between the atoms in a molecule of nitrogen, N2
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Answer:

3 electrons is contributed from each Nitrogen atom.

Total 6 electrons are shared in N₂.

Explanation:

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The electronic configuration of Nitrogen is as:

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Nitrogen form covalent bond and share 3 electron from each side.

total 6 electron are shared between 2 nitrogen atom.

For Covalent bonding it can share its 3 electrons.  

The diagrammatic representation is in attachment.

                   

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