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drek231 [11]
3 years ago
5

Which lists the elements in order from least conductive to most conductive?

Chemistry
2 answers:
Savatey [412]3 years ago
7 0

Answer: Option (A) is the correct answer.

Explanation:

Nitrogen is a non-metal and it is known that non-metals do not conduct electricity. Thus, it will be least conductive out of the given options.

Whereas antimony (Sb) is a metalloid. Metalloid are the substance that show properties of both metals and non-metals. Thus, antimony will conduct electricity.

On the other hand, bismuth (Bi) is a metal hence, it will conduct electricity.

Thus, we can conclude that the order from least conductive to most conductive will be nitrogen (N), antimony (Sb), bismuth (Bi).

 

Vera_Pavlovna [14]3 years ago
3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Conductivity of an element is defined as the tendency to conduct electricity. This property is shown mostly by metals and then by some metalloids and least by non-metals.

Metals are defined as the elements which loose electrons easily and thus can easily conduct electricity due to the presence of free electrons.

Metalloids are defined as the elements which show the properties of both metals and non-metals. Some metalloids are conductive, some are not.

Non-metals are defined as the elements which gain electrons easily and thus cannot conduct electricity easily and are considered as non-conductive.

From the given options:

All the three elements belong to same group but nitrogen is a non-metal, antimony is a metalloid and Bismuth is a metal.

Thus, the order of conductivity follows:

\text{Nitrogen }

Hence, the correct answer is Option A.

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If you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
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Moles= \frac{46.85\ g}{299.4\ g/mol}

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Moles= \frac{125.5\ g}{46.07\ g/mol}

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