The anode is the electrode where the oxidation occurs.
Cathode is the electrode where the reducction occurs.
Equations:
Mn(2+) + 2e- ---> Mn(s) Eo = - 1.18 V
2Fe(3+) + 2e- ----> 2 Fe(2+) 2Eo = + 1.54 V
The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.
Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72
Answer: 2.72 V
A
single oxygen has atomic number 8 that means the nuclei of all oxygen atoms
have eight protons. The number of minus-charged electron is two but the number
of electrons is 10. <span>To gain a minus two-charge ion, it
must have two more negative electrons than positive charged protons. With this,
the ion has 10 electrons, which give it a -2 net charge. </span>
