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Aneli [31]
3 years ago
11

When a sodium atom bonds with a chlorine atom , it acquires positive charge true or false?

Chemistry
2 answers:
VikaD [51]3 years ago
5 0

true

hope this helps

heh

have a nice day

ArbitrLikvidat [17]3 years ago
3 0
True.

The sodium atom becomes a positive ion and the chlorine atom becomes a negative charge because the sodium atom loss an electron and the chlorine atom gained an electron.
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Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque
Andrei [34K]

Answer: Magnesium Mg

Explanation:

Oxidization is the process by which a substance either gains oxygen or losses electrons.

The chemical reaction of the above is denoted by,

Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)

Mg went from a 0 to a +2 state which would mean that it lost electrons.

It was therefore oxidized.

Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.

5 0
3 years ago
Put the following in order of size starting with the smallest and ending with the largest.
malfutka [58]

Answer:

moon, planet, sun, solar system, galaxy, Universe

Explanation:

I am not fully sure but I think this is right

but I apologize if it is wrong

5 0
3 years ago
Given the following information:
bonufazy [111]

Answer:

Ya'll should really practice more because things like these are easy

Explanation:

6 0
2 years ago
Determine the mass of sodium carbonate required to produce 23.4g of sodium chloride when it reacts with excess hydrochloric acid
Leni [432]
The balanced chemical reaction for the described reaction above is,
                          Na2CO3 + 2HCl ---> 2NaCl + H2CO3
From the reaction, 1 mole of Na2CO3 is needed to produce 2 moles of NaCl. In terms of mass, 106 grams of Na2CO3 are needed to produce 116.9 grams of NaCl. From this,
                (23.4 g NaCl) x (106 g Na2CO3 / 116.9 NaCl = 21.22 g Na2CO3
Thus, approximately 21.22 g Na2CO3 is needed for the desired reaction. 
8 0
3 years ago
If a reaction vessel initially contains 5 mol S and 10 mil O2, how many moles of S will be in the reaction vessel once the react
Alex_Xolod [135]

Answer:

Explanation:

2S       +       3O₂       =       2SO₃

2moles      3 moles

2 moles of S react with 3 moles of O₂

5 moles of S will react with 3 x 5 / 2 moles of O₂

= 7.5 moles of O₂ .

O₂ remaining unreacted = 10 - 7.5 = 2.5 moles .

All the moles of S will exhausted in the reaction and 2.5 moles of oxygen will be left .  

6 0
3 years ago
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