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Natasha2012 [34]
3 years ago
15

Can yall answer the question on the image PLEASE

Chemistry
1 answer:
Brut [27]3 years ago
6 0
Answer is 67.8%

To find the percent yield the equation is actual yield over theoretical yield, and multiply by 100. In this problem it is 4.06996 / 6 = 0.678 x 100 = 67.8%
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Número cuántico que designa el nivel de energía en el que se localiza un electrón:
Fed [463]

Answer:

Creo que la respuesta es n. Transalation : I think the answer is N.

Explanation:

4 0
3 years ago
Question 22 A VHF television station assigned to channel transmits its signal using radio waves with a frequency of . Calculate
aleksklad [387]

The question is incomplete, here is the complete question:

A VHF television station assigned to channel transmits its signal using radio waves with a frequency of 66.0 MHz. Calculate the wavelength of the radio waves. Round your answer to 3 significant digits.

Answer: The wavelength of the radio waves is 4.54 m

<u>Explanation:</u>

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light

c = speed of light = 3\times 10^8m/s

\nu = frequency of light = 66.0MHz=66.0\times 10^6s^{-1}

Putting the values in above equation, we get:

\lambda=\frac{3\times 10^8m/s}{66.0\times 10^{6}s^{-1}}=4.54m

Hence, the wavelength of the radio waves is 4.54 m

6 0
4 years ago
Which one of the following represents a<br> chemical change?
11111nata11111 [884]
We need options... sorry
5 0
3 years ago
A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

7 0
3 years ago
Which substance is an electrolyte? 1. O2 2. Xe 3. C3H8 4. KNO3
Troyanec [42]
KNO3 is an electrolyte
3 0
3 years ago
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