2 years ago

Can yall answer the question on the image PLEASE

1 answer:

6 0

Answer is 67.8%

To find the percent yield the equation is actual yield over theoretical yield, and multiply by 100. In this problem it is 4.06996 / 6 = 0.678 x 100 = 67.8%

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Explanation:

Half life of cesium-137 = 30.17 years

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Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

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Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

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Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

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