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3 years ago

What did scientists discover about the ocean floor after sonar was invented?

1 answer:

7 0

<span>led to the discovery of many new sea floor features of smaller scales. Deep sea trenches and sea volcanoes.
If that helped please mark brainliest! <3

-Procklownyt</span>

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How do you fill in the chart and all of 5?

Advocard [28]

You add them and then subtract them

6 0

3 years ago

HELP PLEASE!!!!!

Novay_Z [31]

C wave transfer energy, but not matter this because waves transfer energy from one place to the other without moving matter:) hope this helps!

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3 years ago

Text 8.7 Using the virial equation of state for hydrogen at 298 K given in problem 7 (text 8.6), calculate a. The fugacity of hy

gregori [183]

Answer:

a). P = 688 atm

b). P = 1083.04 atm

c).Δ G = 16.188 J/mol

Explanation:

a). Fugacity 'f' can be calculated from the following equations :

$\ln \frac{f}{P}=\int^P_0\left(\frac{Z-1}{P}\right) dP$

where, P = pressure , Z = compressibility

Now, the virial equation is :

$PV=R(1+6.4\times 10^{-4} P)$ ........(1)

Also, PV=ZRT for real gases .......(2)

∴ $ZRT=RT(1+6.4\times 10^{-4} P)$

$Z=1+6.4\times 10^{-4} P$

So from the fugacity equation ,

$\ln \frac{f}{P}=\int^P_0\left(\frac{1+6.4\times 10^{-4}P-1}{P}\right) dP$

$\ln \frac{f}{P}=\int^P_0\left(\frac{6.4\times 10^{-4}P}{P}\right) dP$

$\ln \frac{f}{P} = 6.4 \times 10^{-4} P$

$f=Pe^{6.4 \times 10^{-4} P}$

Putting the value of P = 500 atm in the above equation, we get,

f = 688 atm

b). Given f = 2P

$2P=PE^{6.4 \times 10^{-4}P}$

$2=E^{6.4 \times 10^{-4}P}$

$\ln 2 = 6.4 \times 10^{-4}P$

∴ P = 1083.04 atm

c). dG = Vdp -S dt at constant temperature, dT = 0

Therefore, dG = V dp

$\int^{G_2}_{G_1}dG =\int^{P_2}_{P_1}V dp$

$=\int^{P_2}_{P_1}\frac{RT}{P}\left(1+6.4 \times 10^{-4}P\right) dP$

$=\int^{P_2}_{P_1}RT\frac{dp}{P}+\int^{P_2}_{P_1}RT6.4 \times 10^{-4} dP$

$\Delta G=R[\ln\frac{P_2}{P_1}+6.4 \times 10^{-4}(P_2-P_1)]$

$\Delta G=8.314\times 298[\ln\frac{500}{1}+6.4 \times 10^{-4}(500-1)]$

Δ G = 16.188 J/mol

7 0

3 years ago

A solution is known to contain either Ni2 or Cr3 . Addition of what single (1 only) reagent would identify which ion is present?

galina1969 [7]

Answer:

Explanation:

From the periodic table; both elements given are from the same group 3.

To test for which ion will be present in the experiment;

We added 6M aqueous sodium hydroxide in excess.

This process is followed by the addition of hydrogen peroxide H2O2 while stirring.

Heat is then applied to the solution.

After we've carried out those process;

We will notice the following;

If $Ni^{2+}$ is present, then a green $NI(OH)_2$ precipitate will be formed

If $Cr^{3+}$ is present,then a yellow-colored $CrO^{2-}_{4}$ will be formed.

6 0

3 years ago

2NH4Cl(aq) + Ba(OH)2(aq) -> BaCl2(aq) + 2NH3(aq) + 2H2O(1)

Akimi4 [234]

How do I answer that.

7 0

3 years ago