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san4es73 [151]
3 years ago
7

Solved, can someone check it over! ​

Physics
1 answer:
kakasveta [241]3 years ago
4 0

Answer:

its good no need to change anything :))

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Which substance is a compound Li, N2, H2, CO2?
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Carbon dioxide is a compound (CO2). The other are just considered molecules since they are bonded to themselves. Lithium (Li) is an element since it's on its own and hasn't formed a bond yet.
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A particle moves in a straight line so that time t seconds its displacement is x metres from a fixed point is given by x=3t^2 +2
Andru [333]

Answer:

-5 meters

Explanation:

x = 3t² + 2t − 5

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x = 3(0)² + 2(0) − 5

x = -5

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Answer: Your question does not make sense

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4 years ago
Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has
k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0
3 years ago
If 56.5 m3 of a gas are collected at a pressure of 455 mm Hg, what volume will the gas occupy if the pressure is changed to 632
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Assuming ideal conditions, Boyle's law says that

<em>P₁ V₁ </em>= <em>P₂</em> <em>V₂</em>

where <em>P₁ </em>and <em>V₁</em> are the initial pressure and temperature, respectively, and <em>P₂</em> and <em>V₂</em> are the final pressure and temperature.

So you have

(455 mm Hg) (56.5 m³) = (632 mm Hg) <em>V₂</em>

==>   <em>V₂</em> = (455 mm Hg) (56.5 m³) / (632 mm Hg) ≈ 40.7 m³

4 0
3 years ago
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