Answer:
7.93 lbs is equal to 3596.987 grams.
Explanation:
The weight in grams is equal to the pounds multiplied by 453.59237.
So... you would multiply 7.93 by 453.59237.
7.93 x 453.59237 = 3596.987
Hope that helped!
Given
Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied
force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient
of kinetic friction µk = 0.3. If a force P
is applied to the body, no relative motion will take place until the applied
force is equal to the force of friction Ff, which is acting opposite to the
direction of motion. Magnitude of static force of friction between block A and
block B, Fs = µsN, where N is
reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA +
mB)a,
6 = (20 / 32.2 + 50 / 32.2)a
2.173a = 6
A = 2.76 ft/s^2
To check slipping occurs between block A and block B, consider block A:
P – Ff = mAaA
6 – Ff = 1.71
Ff = 4.29 lb
And also,
N = wA. We know static friction,
Fs = µsN
Fs = 0.4 x 20
Fs = 8lb
Frictional force is less than static friction. Ff < Fs
<span>Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of
block B aB = 2.76 ft/s^2</span>
Answer:
78.498N
Explanation:
The Net force provided by the spinnaker can be obtained from Newton's second law of motion as follows;

where m is the mass, v is the final velocity, u is the initial velocity and t is the time interval for which the force acted.
Given;
m =980lb
v = 12mi/h
u =8mi/hr
t = 10s.
It is important to convert all quantities to their SI units where necessary, so we do that as follows;
1lb = 0.45kg,
hence 980lb = 980 x 0.45kg = 441kg.
1mile = 1609.34m
1hour = 3600s,
therefore;


Substituting all values into equation (1), we obtain the following;

Answer:
Explanation:
Initial kinetic energy of the system = 1/2 mA v0²
If Vf be the final velocity of both the carts
applying conservation of momentum
final velocity
Vf = mAvo / ( mA +mB)
kinetic energy ( final ) = 1/2 (mA +mB)mA²vo² / ( mA +mB)²
= mA²vo² / 2( mA +mB)
Given 1/2 mA v0² / mA²vo² / 2( mA +mB) = 6
mA v0² x ( mA +mB) / mA²vo² = 6
( mA +mB) / mA = 6
mA + mB = 6 mA
5 mA = mB
mB / mA = 5 .
Answer:
- <u>First choice:</u><u><em> Because the mass of the cannon ball is much less than the cannon</em></u>
Explanation:
Indeed, <em>Newton's Third Law</em>, i.e. the action-reaction law, states that any action (force) will have a reaction (force) of same magnitude but opposite direction.
That means that when a cannon goes off the cannon ball exerts a force on the cannon and the cannon exerts the same force back on the cannon ball.
To find out how much the cannon ball and the cannon itsel move, you must consider Newton's second law.
- F = m×a (force equal mass times acceleration).
Clearing the acceleration you get:
Then, since the mass is in the denominator and both the force that the cannon ball exerts on the cannon and the cannon exerts on the cannon ball are equal in magnitude, then the body that has the smaller mass (the cannon ball) will experience a greater acceleration, which is stated by the first choice: because the mass of the cannon ball is much less than the cannon.