The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.
Given mean of 14 years, variance of 25 and sample size is 50.
We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.
μ=14,
σ=
=5
n=50
s orσ =5/
=0.7071.
This is 1 subtracted by the p value of z when X=12.5.
So,
z=X-μ/σ
=12.5-14/0.7071
=-2.12
P value=0.0170
1-0.0170=0.9830
=98.30%
Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.
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There is a mistake in question and correct question is as under:
What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?
To figure out the number we need to set up our equation to make more sense.
<u>3/5 = 30/x</u> (x is our missing number)
We know that what ever you do to the top of the fraction you can do to the bottom.
So if we multiply 3 x 10 we get 30.
Therefore to get the number we must multiply 5 by 10
5 x 10 = 50
So our answer and missing number is 50
Answer:
x = 7, x = -3
Step-by-step explanation:
(x - 2)^2 = 25
Take the square root of each side
sqrt((x - 2)^2) =±sqrt( 25)
x-2 = ±5
Add 2 to each side
x-2+2 = 2±5
x = 2±5
x = 2+5, x=2-5
x = 7, x = -3
1 cm equals to 10 mm, therefore 7000 mm = 700 cm.