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abruzzese [7]
3 years ago
11

7. Fredrick wanted to find out what soil works best for growing roses. He grew them in potting

Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

Dependent variable are those variables that changes with the change in variables that affects it. (IG - leo_muan)

Explanation:

Dependent variable responds or gets affected to change. They are not constant. It can be possible that dependent variable is relying on independent variable as independent variable does not change with change of any of the factor in an experiment.  

Sometimes, mentioning not the units leads to insufficient data of the variables. A constant is something whose value cannot be changed and is used for comparison purpose. According to the question, Rose is constant, height is dependent variable , different types of soil are independent variable.  

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Do constellations appear the same in Northern and Southern Hemisphere? Why or Why Not?
Mashcka [7]
The visible constellations<span> are definitely different between the Northern and Southern Hemispheres. In general, at any given point on Earth, only around 50% of the sky will be visible. We can understand this by considering the atmosphere as a sphere around the earth. The sky any person can view at one point can be compared to a giant dome equal to half of the sphere. And because the Earth rotates, the dome we can see changes, unless one is sitting directly on the North or South Pole.</span>
5 0
4 years ago
Construct a simulated proton-decoupled 13C NMR spectrum for tert-butyl alcohol. Drag the resonance signal icon to the appropriat
atroni [7]

Answer:

                     The ¹³C-NMR Spectrum of  <em>tert</em>-butyl alcohol will show only two signals.

(i) Signal at around 31 ppm:

                                              This signal towards upfield is for the carbon atoms which are more shielded and are having rich electron surroundings. The height of peak at y-axis shows the number of carbon atoms as compared to other peaks. In this case it is three times the height of second signal hence, it shows that this peak corresponds to three carbon atoms.

(ii) Signal at around 70 ppm:

                                              This signal towards downfield is for the carbon atom which is more deshielded and is having electron deficient surrounding. As compared to the second signal the height of this peaks corresponds to only one carbon. And the deshielded environment shows that this carbon is directly attached to an electronegative element.

4 0
4 years ago
During a period of discharge of a lead-acid battery, 405 g of Pb from the anode is converted into PbSO4 (s).
Alexus [3.1K]

Answer:

The answers to the question are as follows

First part

The mass of PbO2 (s) reduced at the cathode during the period is = 467.55_g

Second part

The electrical charge are transferred from Pb to PbO2 is 377186.86_C or 3.909 F  

Explanation:

To solve this, we write the equation for the discharge of the lead acid battery as

H₂SO₄ → H⁺ + HSO₄⁻

Pb (s) + HSO⁻₄ → PbSO₄ + H⁺ + 2e⁻

at the cathode we have

PbO₂ + 3H⁺ + HSO⁻₄ + 2e⁻ → PbSO₄ + 2H₂O

Summing the two equation or the total equation for discharge is

Pb (s) + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O

From the above one mole of lead and one mole of PbO₂  are consumed simultaneously hence

Number of moles of lead contained in 405 g of Pb with molar mass  = 207.2 g/mole = (405 g)/ (207.2 g/mole) = 1.95 mole of Pb

Hence number of moles of  PbO₂ reduced at the cathode = 1.95 mole

mass of  PbO₂ reduced at the cathode = (number of moles)×(molar mass)

= 1.95 mole × 239.2 g/mol = 467.55 g of Lead (IV) Oxide is reduced at the cathode

Part B

Each mole of Pb transfers 2e⁻ or 2 electrons, therefore 1.95 moles of Pb will transfer 2 × 1.95 = 3.909 moles of electrons transferred

Each electron carries a charge equal to -1.602 × 10⁻¹⁹ C or one mole of electrons carry a charge equal to 96,485.33 coulombs

hence 3.909 moles carries a charge = 3.909 × 96,485.33 coulombs =377186.86 Coulombs of electrical charge

or transferred electrical charge = 377186.86 C or 3.909 Faraday

6 0
3 years ago
If a sample of gas has a volume of 100.0ml when the pressure is 50.0kPa, what is volume when the pressure is increased to 400.0k
dalvyx [7]

Answer:

V₂ = 12.5 mL

Explanation:

Given data:

Initial volume = 100.0 mL

Initial pressure = 50.0 KPa

Final volume = ?

Final pressure = 400.0 KPa

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

50.0 KPa × 100.0 mL = 400 KPa × V₂

V₂ = 5000 KPa.mL/ 400 KPa

V₂ = 12.5 mL

6 0
3 years ago
However, compared to the other options, lead is too
fenix001 [56]

Answer:

dangerous and heavy

Explanation:

just did it!

7 0
2 years ago
Read 2 more answers
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