Answer:
(A) 15.0 °C
Explanation:
The water in beaker A gains heat because its initial temperature (10 °C) is less than the initial temperature of the water in beaker B (20 °C) which loses heat.
Let T3 be the final temperature
Heat gained by beaker A = heat loss by beaker B
mc(T3 - T1) = mc(T2 - T3)
The mass and specific heat of water in both beakers are the same. Therefore, (T3 - T1) = (T2 - T3)
T1 is initial temperature of beaker A = 10 °C
T2 is initial temperature of beaker B = 20 °C
T3 - 10 = 20 - T3
T3 + T3 = 20 + 10
2T3 = 30
T3 = 30/2 = 15 °C
Substances have different tendencies to donate or accept electrons. When a really good donor meets a great acceptor, the chemical reaction releases a lot of energy. Oxygen (O2) is the best electron acceptor and is used in many aerobic reactions (reactions with oxygen). Hydrogen gas (H2) is a good electron donor.
When O2 and H2 are combined, along with a catalyst, water (H2O) is formed. This example of a redox reaction can be written like this:

Answer:
H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)
Explanation:
We must recall that the oxides of metals are bases. These metal oxides can react with dilute acids to yield salt and water.
Bearing that in mind, we want to obtain magnesium sulfate from a metal oxide and dilute acid.
In this case we need magnesium oxide and dilute sulphuric acid. The reaction occurs as follows;
H2SO4(aq) + MgO(s) → H2O(l) + MgSO4(aq)
Answer:D.
Explanation:i used photo math. It is really helpful when I'm doing math homework etc...
CaBr conducts electricity in the molten state but does not conduct as a solid. ionic dissolution equation.
