The given quadrilateral is a kite.
Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)
Firstly, we find the distance between AD and DC
AD = 
⇒ AD = 
⇒ AD = 5
DC = 
⇒ DC = 
⇒ DC = 5
Hence, AD = DC = 5
Now, find the distance between AB and BC
AB = 
⇒ AB = 
⇒ AB = 
⇒ AB = 
BC = 
⇒ BC = 
⇒ BC = 
⇒ BC = 
Hence, AB = BC = √97
In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.
Hence, it follows the property of kite.
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Answer:
56,149 would be left over
Step-by-step explanation:
56,941-792=56,149
Answer:
Given: DB = 7.2 cm, AE = 1.8 cm and EC = 5.4 cm and DE || BC.
DB
AD
=
AC
AE
[by basic proportionality theorem which states that if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same.
7.2
AD
=
5.4
1.8
AD=
5.4
7.2×1.8
AD=
10
24
⟹AD=2.4cm
Answer:
4/7 = 8/14
Step-by-step explanation: