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3 years ago

Are 2b+ b and 3b equivalent expressions?

Mathematics

1 answer:

MAVERICK [17]3 years ago

5 0

Answer:

yes

Step-by-step explanation:

2b+b=3b because2+1 = 3

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Complete the inequality.

Vitek1552 [10]

Answer:

Step-by-step explanation:

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3 years ago

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Simplify the polynomial expressions by combining like terms and then multiply the resulting binomial expressions to find their p

patriot [66]

(6x-9)(8+5x-5)=(6x-9)(5x+3)=

$=6x\cdot5x-5x\cdot9+6x\cdot3-9\cdot3=\\=30x^2-27x-27$

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3 years ago

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A 100 inch strip of sheet metal starting out 16 inches wide is to be made into a small open trough (open top and ends) by turnin

daser333 [38]

Answer:

4 inches should be turned up on both sides.

Step-by-step explanation:

In order to find this, create a situation in which we give the amount turned up on each side as x. Then give the amount that isn't turned up as 16 - 2x (since 2x is the amount turned up). Now we can find the area by multiplying the 3 measurements.

100 * x * (16 - 2x) = MAX

100 * (16x - 2x^2) = MAX

-200x^2 + 1600x = MAX

Now that we have a quadratic function, we can find the maximum value of x by using the vertex formula for x values (-b/2a).

x = -b/2a

x = -1600/2(-200)

x = -1600/-400

x = 4

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3 years ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

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3 years ago

In the past year, Hans watched 38 movies that he thought were very good. He watched 95 movies over the whole year. Of

Len [333]

Answer:

40%

Step-by-step explanation:

38×100=3800÷95=40

40%×95=38

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3 years ago