Question

Estimate the force required to bind the two protons in the He nucleus together. (Hint: Model the protons as point charges. Assume the diameter of the He nucleus to be approximately 10-15 m.

Answer 1

Answer:

 F = 2.30 10⁴ N

Explanation:

The force required to link two gates must be equal to or greater than the electrostatic force of repulsion, because the protons have equal charges.

                 F = k q₁ q₂ / r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C²

   In this case the proton charge is 1.6 10⁻¹⁹ C and the distance between them is approximately the diameter of the core r = 10⁻¹⁵ m

Let's calculate

              F = 8.99 10⁹ (1.6 10⁻¹⁹)² / (10⁻¹⁵)²

              F = 2.30 10⁴ N

The bond strength must be equal to or greater than this value