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3 years ago

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Estimate the force required to bind the two protons in the He nucleus together. (Hint: Model the protons as point charges. Assum

e the diameter of the He nucleus to be approximately 10-15 m.

1 answer:

scoray [572]3 years ago

3 0

Answer:

F = 2.30 10⁴ N

Explanation:

The force required to link two gates must be equal to or greater than the electrostatic force of repulsion, because the protons have equal charges.

F = k q₁ q₂ / r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C²

In this case the proton charge is 1.6 10⁻¹⁹ C and the distance between them is approximately the diameter of the core r = 10⁻¹⁵ m

Let's calculate

F = 8.99 10⁹ (1.6 10⁻¹⁹)² / (10⁻¹⁵)²

F = 2.30 10⁴ N

The bond strength must be equal to or greater than this value

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Answer:

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Explanation:

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3 years ago

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A toy balloon contains 0.75 L of helium at a pressure of 101 kPa. The balloon rises until the pressure on the balloon is 85 kPa.

Aleksandr [31]

<h3>The answer is 0.89 L</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{101000 \times 0.75}{85000} = \frac{75750}{85000} \\ = 0.89117647...$

We have the final answer as

<h3>0.89 L</h3>

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3 years ago

A waterbed has a force of 1300N on the floor. It exerts 347 Pa of pressure. What is the area of the waterbed?

Sergio [31]

Answer:

Pressure = Force/Area

347 = 1300/Area

Area = 1300/347

area= 3.47m2

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3 years ago

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A student sits on a rotating stool holding two 3.09-kg masses. When his arms are extended horizontally, the masses are 1.08 m fr

schepotkina [342]

Answer:

a

The New angular speed is $w_f = 2.034 rad/s$

b

The Kinetic energy before the masses are pulled in is $KE_i = 3.101 \ J$

c

The Kinetic energy after the masses are pulled in is $KE_f = 8.192 \ J$

Explanation:

From the we are told that masses are 1.08 m from the axis of rotation, this means that

The radius $r =1.08m$

The mass is $m = 3.09\ kg$

The angular speed $w = 0.770 \ rad/sec$

The moment of inertia of the system excluding the two mass $I = 3.25 \ kg \cdot m^2$

New radius $r_{new} = 0.34m$

Generally the conservation of angular momentum can be mathematical represented as

$w_f = [\frac{I_i}{I_f} ]w_i .....(1)$

Where $w_f$ is the final angular speed

$w_i$ is the initial angular speed

$I_i$ is the initial moment of inertia

$I_f$ is the final moment of inertia

Moment of inertia is mathematically represented as

$I = m r^2$

Where I is the moment of inertia

m is the mass

r is the radius

So the Initial moment of inertia is given as

$I_i = moment \ of \ inertia \ of\ the \ two \ mass \ + 3.25 \ kg \cdot m^2$

$I_i = 2m r^2 + 3.25$

The multiplication by is because we are considering two masses

$I_i = 2 [(3.09)(1.08)^2] +3.25 = 10.46 kg \cdot m^2$

So the final moment of inertia is given as

$I_f = 2[(3.09)(0.34)^2] +3.25 = 3.96 \ kg \cdot m^2$

Substituting these values into equation 1

$w_f = [\frac{10.46}{3.96} ] * 0.77 = 2.034 \ rad/sec$

Generally Kinetic energy is mathematically represented in term of moment of inertia as

$KE = \frac{1}{2} * I * w^2$

Now considering the kinetic energy before the masses are pulled in,

$KE_i = \frac{1}{2} * I_i * w^2_i$

The Moment of inertia would be $I_i = 10.46 \ Kg \cdot m^2$

The Angular speed would be $w_i = 0.77 \ rad/s$

Now substituting these value into the equation above

$KE_i = \frac{1}{2} * (10.46) * (0.770)^2 = 3.101 J$

Now considering the kinetic energy after the masses are pulled in,

$KE_f = \frac{1}{2} * I_f * w^2_f$

The Moment of inertia would be $I_f = 3.96 \ Kg \cdot m^2$

The Angular speed would be $w_f = 2.034 \ rad/s$

Now substituting these value into the equation above

$KE_f= \frac{1}{2} *(3.96)(2.034)^2$

$= 8.192J$

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3 years ago

How does the long-run equilibrium for a monopolistically competitive market differ from the long-run equilibrium for a perfect

Katen [24]

Answer and Explanation:

The main difference between monopolistic competition and perfect competitive market are given bellow

Excess capacity : There is constantly an overabundance limit in monopolistic challenge and not in the ideal challenge. Over the long haul, superbly aggressive firms produce at the proficient scale,where as monopolistically focused firms produce beneath this level. Firms are said to have abundance limit under monopolistic challenge. As it were, a monopolistically focused firm, in contrast to a splendidly aggressive firm, could build the amount it delivers and lower the normal all out expense of generation.

Markup over marginal cost: the another distinction between flawless challenge and monopolistic challenge is the connection among cost and minor expense. At an aggressive firm consistently cost equivalents negligible expense. Where as, in monopolistically aggressive firm, cost surpasses minimal expense becouse the firm consistently have some market control.

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2 years ago