Answer: Potassium is 39.10 g/mol
Explanation: The numbers below the element are the molar mass.
Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Answer: NaCl>HCl&H2O> N2
Explanation:
NaCl, as an ionic substance has a very high boiling point as expected. However, the boiling points of HCl and H2O depend on the relative concentration of the HCl and water, at 20% HCl, it boils at almost the same temperature as water due to extensive intermolecular hydrogen bonding. N2 comprises only of Vanderwaals forces hence it has the least boiling point.
Answer:
Three main parts are Protons (pos charge) Neutrons (no charge) Electrons (negative charge) and the electron is found on the outside of the nucleus
Explanation:
Answer:
1.95mol
Explanation:
First let us generate the equation for the reaction:
2H2 + O2 —> 2H2O
From the equation,
1mole of O2 reacted to produce 2moles of H2O.
Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e
Xmol of O2 = 3.9/2 = 1.95mol
