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2 years ago

Saftey goggles are worn in the lab-

Chemistry

1 answer:

Harrizon [31]2 years ago

4 0

Answer:

Yes

Explanation:

Is this a question or what?

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What chemical compound is crucial to marine life and how is it disappearing?

daser333 [38]

Nitrogen is crucial to the marine life and it is disappearing because it cannot be assimilated by most organisms in the water.

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2 years ago

Which substance is a compound iron or nitrogen oxide

Zanzabum

I think it might be Nitrogen dioxide, but please check behind

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2 years ago

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A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati

Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.

$\text{calculating the initial HI}= \frac{mol}{V}$

$=\frac{9.3 \times 10 ^ -3}{2}$

$=0.00465 \ Mol$

$\text{Similarly}\ \ I_2 \ \ \text{follows} \ \ H_2 = 0 }$

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

$HI = 0.00465 - 2x\\\\ I_{2} \ eq = H_2 \ eq = 0 + x \\\\$

It is defined that:

$I_2 = 6.29 \times 10^{-4} \ M \\\\x = I_2 \\\\$

$HI \ eq= 0.00465 - 2x \\$

$=0.00465 -2 \times 6.29 \times 10^{-4} \\\\ = 0.00465 -\frac{25.16 }{10^4} \\\\ = 0.003392\ M$

Now, we calculate the position:

For the reaction $H 2(g) + I 2(g)\rightleftharpoons 2HI(g)$ , you can calculate the value of Kc at 1000 K.

data expression for Kc

$2HI \rightleftharpoons H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}$

$= \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386$

calculating the reverse reaction

$H_2(g) + I_2(g)\rightleftharpoons 2HI(g)$

$Kc = \frac{1}{Kc} \\\\$

$= \frac{1}{0.034386}\\ \\= 29.081\\$

7 0

2 years ago

{Plz answer} Thank you!

Dafna11 [192]

The Answer to your question would be A

8 0

3 years ago

Read 2 more answers

A 253 g block of wood has the following dimensions: Length 15.24 cm Width 6.64 cm Height 3.56 cm What is the density of the wood

yanalaym [24]

Answer:

0.7 g/cm³

Explanation:

hey there,

< The formula for density is $p = \frac{m}{v}$ where m = mass, v = volume, and p = density. An easy way to remember the formula is density equals love. I found this easy to remember because p = ♡ and when you think about it, if you split the heart in half through the middle like a fraction, it will make $\frac{m}{v}$ (if you don't understand what I'm saying, try writing it out and you will be able to see what I'm talking about!)

We already know that the block is 253 g so the mass is 253 g.

To find the volume, always multiply the 3 values width, length, and height whenever you are trying to find the volume of a block.

15.24 cm x 6.64 cm x 3.56 cm = 360.25 cm³

Now plug it into the formula. $p = \frac{m}{v}=\frac{253}{360.25} = 0.7 g/cm$ ³ >

Hope this helped! Feel free to ask anything else.

4 0

2 years ago

Saftey goggles are worn in the lab- ​

Saftey goggles are worn in the lab-