Question

To what Kelvin temperature must a balloon

Answer 1

Answer:

$T_2=261.46\ K$

Explanation:

It is given that,

Original temperature, $T_1=323^{\circ}C=596.15\ K$

Original volume, $V_1=2.85\ L$

We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.

According to Charles law, at constant pressure, $V\propto T$

It would means, $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

T₂ = ?

$T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.25\times 596.15}{2.85}\\\\T_2=261.46\ K$

So, the new temperature is 261.46 K.