Answer: option <span>B.The total mass of A and C, which are carbon and oxygen, is equal to the mass of B, which is carbon dioxide.
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Explanation:
1) The combustion of carbon is represented by the chemical equation:
C + O₂ → CO₂
2) The law of conservation of mass states that the mass of the products is equal to the mass of the reactants.
3) The reactants are C and O₂, while the product is CO₂.
4) The masses given are: A: 12 g, B: 44 g, and C: 32 g
Then, 12g + 32 g = 44 g, this is A + C = B.
Then, B represents the product, which is CO₂, whose molar mass is 44 g/mol.
Since, the molar mass of C is 12 g/mol, it is A; and since the molar mass of O₂ is 32, it is C.
Therefore, the answer is the option B.
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Answer:
3.1°C
Explanation:
Using freezing point depression expression:
ΔT = Kf×m×i
<em>Where ΔT is change in freezing point, Kf is freezing point depression constant (5.12°c×m⁻¹), m is molality of the solution and i is Van't Hoff factor constant (1 For I₂ because doesn't dissociate in benzene).</em>
Molality of 9.04g I₂ (Molar mass: 253.8g/mol) in 75.5g of benzene (0.0755kg) is:
9.04g ₓ (1mol / 253.8g) = 0.0356mol I₂ / 0.0755kg = 0.472m
Replacing in freezing point depression formula:
ΔT = 5.12°cm⁻¹×0.472m×1
ΔT = 2.4°C
As freezing point of benzene is 5.5°C, the new freezing point of the solution is:
5.5°C - 2.4°C =
<h3>3.1°C</h3>
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Answer:
1.7 M
Explanation:
Given data:
Mass of AgNO₃ = 29.66 g
Volume of solution = 100 mL (100/1000 = 0.1 L)
Molarity of solution = ?
Solution;
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 29.66 g/ 169.87 g/mol
Number of moles = 0.17 mol
Molarity of solution:
Molarity = moles of solute / volume of solution in L
Molarity = 0.17 mol / 0.1 L
Molarity = 1.7 M
Answer:
177253.125hrs
Explanation:
Given parameters:
Number of hours spend per day on phone = 6.25hrs
Unknown:
Average hours pend by an average American if they lived for 77.7yrs
Solution:
Let us find the number of hours an average American spends on their phone per year;
there are 365days in a year
Number of hours = 365 x 6.25 = 2,281.25hrs
Now, if they lived for 77.7yrs;
They will spend = 77.7 x 2,281.25 = 177253.125hrs
Answer: 50%
Explanation:
The number of electron pairs are 2 for hybridization to be
and the electronic geometry of the molecule will be linear.
1. percentage of s character in sp hybrid orbital =![\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{2}\times 100=50\%](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bnumber%20of%20s%20orbitals%7D%7D%7B%5Ctext%20%7Btotal%20number%20of%20orbitals%7D%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20100%3D50%5C%25)
2. percentage of s character in
hybrid orbital =![\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{3}\times 100=33.3\%](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bnumber%20of%20s%20orbitals%7D%7D%7B%5Ctext%20%7Btotal%20number%20of%20orbitals%7D%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%20100%3D33.3%5C%25)
3. percentage of s character in
hybrid orbital =![\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{4}\times 100=25\%](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bnumber%20of%20s%20orbitals%7D%7D%7B%5Ctext%20%7Btotal%20number%20of%20orbitals%7D%7D%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%20100%3D25%5C%25)
Thus percentage of s-character in an sp hybrid is 50%.