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Zarrin [17]
3 years ago
14

Why is melting point considered a physical property

Chemistry
1 answer:
miskamm [114]3 years ago
6 0

Answer:

Because you can physically see the object melting when it comes to the melting point. The objects texture, color, temperature, shape, and state of matter (solid, liquid, gas) are possibly changing.

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A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
6 0
3 years ago
Why does the temperature stop rising while ice melts into water?
Leya [2.2K]
A.
Because no more heat is being added to the system
3 0
3 years ago
Z=3 1s2 express answer as an ion
sashaice [31]

Answer:

The element with electronic configuartion  1s² and atomic number 3 must be an cation.

Explanation:

The "Z" shows the atomic number. Z stand for zahl. It Is German word and meaning is " number".

In given question Z is equal to three which means an element with atomic number three.

Let consider the X is an element with atomic number three having electronic configuration 1s², but according to this atomic number there should be one more electron present is 2s. If X has the electronic configuration 1s² it means that it lose one electron and X is present in the form of cation.

X⁺ =  1s²

7 0
3 years ago
How many joules of heat are needed to raise the temperature of 47.5 g of aluminum from 21°C to 94°C , if the specific heat of al
Montano1993 [528]

Answer:

3120.75J

Explanation:

So, we have the formula q = mc\Delta t. For this example, q is the heat energy in Joules, m is the mass in grams, c is the specific heat capacity in \frac{J}{{g\°C}}, and \Deltat is the change in temperature. In this case, m = 47.5g, c = 0.9  \frac{J}{{g\°C}}, and \Deltat  = 94-21 = 73°C. Plugging in the values, we get the joules of heat required to raise 47.5g of Al from 21°C to 94°C which is stated above. You can double check my answer but that should be it. An important thing to be aware of are the units. Sometimes, the heat capacity may not be \frac{J}{{g\°C}}. I may be in Kelvin or something. Anyways, hope this helps.

5 0
4 years ago
How many Tootsie Rolls can you get for 14 Bit o' honey?
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