When the Heat gain or lose = the mass * specific heat * ΔT
and when we have the mass of gold coin= 40 g
and the specific Heat of gold= 0.13 J/g°
and ΔT = (Tf- Ti) = 10°C - 50°C = -40 °C
so by substitution:
∴Heat H = 40 g * 0.13 J/g° * -40
= - 208 J
Answer:
1 & 4
Explanation:
just got it right on edge
