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3 years ago

11

Hydrogen, when combined with nitrogen in a chemical reaction, forms ammonia. Which type of chemical reaction is this an example

of?

1 answer:

larisa86 [58]3 years ago

7 0

Answer: Combination reaction

Explanation:

Hydrogen (H2) combines with nitrogen (N2) to form a single compound, ammonia (NH3) in a combination reaction.

The chemical equation is as follows:

N2(g) + 3H2(g) --> 2NH3(g)

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2. A 2.75 kg sample of a substance occupies a volume of 250.0 cm^3. Find its density in g/cm.

hichkok12 [17]

Answer:

<h3>The answer is 11 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 2.75 kg = 2750 g

volume = 250 cm³

We have

$density = \frac{2750}{250} \\$

We have the final answer as

<h3>11 g/cm³</h3>

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3 years ago

the solubility product Ag3PO4 is: Ksp = 2.8 x 10^-18. What is the solubility of Ag3PO4 in water, in moles per liter?

guapka [62]

Answer : The solubility of $Ag_3PO_4$ in water is, $1.8\times 10^{-5}mol/L$

Explanation :

The solubility equilibrium reaction will be:

$Ag_3PO_4\rightleftharpoons 3Ag^++PO_4^{3-}$

Let the molar solubility be 's'.

The expression for solubility constant for this reaction will be,

$K_{sp}=[Ag^{+}]^3[PO_4^{3-}]$

$K_{sp}=(3s)^3\times (s)$

$K_{sp}=27s^4$

Given:

$K_{sp}$ = $2.8\times 10^{-18}$

Now put all the given values in the above expression, we get:

$K_{sp}=27s^4$

$2.8\times 10^{-18}=27s^4$

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Therefore, the solubility of $Ag_3PO_4$ in water is, $1.8\times 10^{-5}mol/L$

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3 years ago