The mass is moving with an acceleration of 13.299 m/s².
<h3>What is the straight forward meaning of acceleration?</h3>
The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations.
According to therefore mentioned statement,
the direction of the net force applied on an object determines its acceleration;
according to mentioned data;
F₁=30N
F₂=10N
Net force on object;
F=F₁+F₂
F=F₁y+F₂Cos30°(-x)+F₂ Sinx(-y)
F=3y+10×(√3/2)(-x)+10×(1/2)(-y)
F=ma
ma=-5√3/2(x)+25y
2a=-5√3x/2+25y
a=-5√3x+25y
magnitude(a)=√(-5√3/2)²+(25/2)²
(a) =13.299m/s²
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D, I believe would be the first minus the second vector.
To solve this I named the first vector as A and the second as B.
So... vector A - B = resultant
or A + (-B)
A negative indicates a direction of a vector so if we flip the direction the other way we have the first vector (A) pointing vertically upwards and then vector B pointing to the west.
Now we have to use the head to tail method, meaning that the head of the first vector has to connect with the tail of the other vector added.
So we should have something like this
(-B) < - - - - ^
|
| (A)
|
To add these two vectors, technically A - B, draw a line from the tail of A to the head of -B which would look like image D.
Hope this helped!
Answer:
7.83
Explanation:
Just using the speed ,distance and time relation..Let time be T
Use this formula and find the distance covered by automobile .
Do same for car ..
and at last subtract the distance of automobile to car =141.
i.e (Distance of automobile -Dist.of car )=141
Answer:
v = - 0.4 m/s
Explanation:
Initial momentum is zero as neither gun nor bullet have velocity
Conservation of momentum
0 = 0.020(50) + 2.5v
v = - 0.4 m/s
