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shepuryov [24]
3 years ago
12

Select the organic compounds. Select all that apply. CO C2H6 CH4 CO2 NaCO2

Chemistry
2 answers:
icang [17]3 years ago
7 0

<u>Answer:</u> The organic compounds are C_2H_6\text{ and }CH_4

<u>Explanation:</u>

Organic compounds are defined as the compounds where a covalent bond is present between hydrogen and carbon atoms. These compounds are also known as hydrocarbons.

From the given options:

CO,CO_2\text{ and }NaCO_2 does not have a covalent bond between hydrogen and carbon atoms. Thus, these compounds are not considered as an organic compound.

C_2H_6\text{ and }CH_4 have a covalent bond present between hydrogen and carbon atoms. Thus, these are considered as organic compounds.

Hence, the correct answer is C_2H_6\text{ and }CH_4

RSB [31]3 years ago
6 0
There are only 2 organic compounds present, C2H6 and CH4. The rest are all inorganic compounds.
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An <em>i</em><em>o</em><em>n</em><em>i</em><em>c</em><em> </em><em>b</em><em>o</em><em>n</em><em>d</em> is formed between a metal and a non-metal. Non-metals(-ve ion) are "stronger" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond.

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4 years ago
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

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3 years ago
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Idenatify the pair in which the formula does not match the name
MissTica
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4 years ago
A 21.0 kg child is running at a velocity of 2.50 m/s. The child is carrying a 2.25 kg gallon of milk. What is the momentum of th
KIM [24]

Answer: The momentum of the child and milk together is 58.125 kg.m/s

Explanation:

Momentum is defined as the product of object's mass and velocity.

Mathematically,

p=mv

where, p = momentum

m = mass of the object

v = velocity of the object

In the given question, we are given that a child of mass 21.0 kg is carrying a gallon of milk having mass 2.25 kg and running with a velocity of 2.5 m/s. Hence, the momentum by both milk and child will be:

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Given:

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Putting values in equation 1, we get:

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Hence, the momentum of the child and milk together is 58.125 kg.m/s

7 0
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