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sp2606 [1]
3 years ago
10

Balance the following reactions using either the oxidation number method or the half-reaction method. Identify which element has

been oxidized and which has been reduced.
Ce4+ + I– → Ce3+ + IO3– (in a basic solution)
Chemistry
1 answer:
Marina86 [1]3 years ago
6 0

6Ce^{4+} + I^- + 6OH^- → 6Ce^{3+} + IO_3^- + 3H_2O is the balanced chemical equation.

<h3>What is a balanced chemical equation?</h3>

A balanced chemical reaction is an equation that has equal numbers of each type of atom on both sides of the arrow.

Half-reaction method:

Unbalanced chemical equation:

Ce^{4+} + I^-→ Ce^{3+} + IO^{3-}

Oxidation half-reaction:

I^-+ 6OH^- - 6e- → IO^{3-} + 3H_2O

Reduction half-reaction:

Ce4^+ + e^- → Ce^{3+}

Balanced chemical equation:

6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO^{3-} + 3H_2O

Oxidation number method:

Unbalanced chemical equation:

Ce^{4+} + I^-→ Ce^{3+} + IO^{3-}

I^{-1} -6e^-→ I^{+5}

Ce^{4+} + e^- → Ce^{3+}

Balanced chemical equation:

6Ce^{4+} + I^{-1} → 6Ce^{3+} + I^{+5}

or

6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO_3^- + 3H_2O

Hence, 6Ce^{4+} + I^- + 6OH^-→ 6Ce^{3+} + IO_3^- + 3H_2O is the balanced chemical equation.

Learn more about the balanced chemical equation here:

https://brainly.in/question/46754758

#SPJ1

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Answer:

hydroxide ion

Explanation:

The alkaline battery got this name because it has an alkaline electrolyte of potassium hydroxide.

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2 years ago
At normal atmospheric pressure, water freezes at:
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Water will freeze at 0°C so the answer is b
8 0
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The reaction 2CH4(g)⇌C2H2(g)+3H2(g) has an equilibrium constant of K = 0.154. If 6.30 mol of CH4, 4.20 mol of C2H2, and 11.15 mo
boyakko [2]

Answer:

C₂H₂ + 3H₂ ⟶ 2CH₄  

Explanation:

The initial concentrations are:

[CH₄] = 6.30 ÷ 6.00 =   1.05  mol·L⁻¹

[C₂H₂] = 4.20 ÷ 6.00 = 0.700 mol·L⁻¹

   [H₂] = 11.15 ÷  6.00 =  1.858 mol·L⁻¹

                2CH₄ ⇌ C₂H₂ + 3H₂

I/mol·L⁻¹:    1.05     0.700   1.858

Q = \dfrac{\text{[C$_{2}$H$_{2}$][H$_{2}$]}^{3}}{\text{[CH$_{4}$]}^{2}} = \dfrac{ 0.700\times 1.858^{3}}{1.05^{2}}= 4.07

Q > K

That means we have too many products.

The reaction will go to the left to get rid of the excess products.

C₂H₂ + 3H₂ ⟶ 2CH₄

8 0
4 years ago
If 10.00 mL of the solution prepared in question 4 is used to make another 125.00 mL solution of NaCl, what is the new concentra
choli [55]

The new concentration of the solution is 0.016 M

<h3>Dilution</h3>

From the question, we are to determine the concentration of the new solution prepared from question 4.

NOTE: Question is provided below

From question 4, the concentration of the sodium chloride solution is 0.200M

Now, to determine the new concentration,

Using the dilution law

C₁V₁ = C₂V₂

Where

C₁ is the initial concentration

V₁ is the initial volume

C₂ if the final concentration

and V₂ is the final volume

Then,

C₁ = 0.200 M

V₁ = 10.00 mL
C₂ = ?

V₂ = 125.00 mL

Then,

0.200 × 10.00 = C₂ × 125.00

C_{2}= \frac{0.200 \times 10}{125.00}

C₂ = 0.016 M

Hence, the new concentration of the solution is 0.016 M

Question 4:

Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution

Learn more on Dilution here: brainly.com/question/24881505

8 0
2 years ago
The universe contains only about one-tenth as many helium atoms as hydrogen atoms. But a hydrogen atom is only one-quarter the m
oksano4ka [1.4K]

Answer:

the ratio of the universe's helium to hydrogen by mass is 2:5 approximately.

Explanation:

To solve this question, we assign arbitrary values to these elements in tandem to the data given in the question.

nH, Number of Hydrogen atoms = X = 100

nHe, Number of Helium atoms = 0.1X = Y = 10

From the data given, by mass:

if the mass of Hydrogen atom = 1g = 100g

therefore, the mass of a Helium atom = 4g (1*4) = 40g

Mass ratio of Helium to Hydrogen = 40:100 = 4:10 = 2:5 approximately

8 0
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