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Nataly_w [17]
3 years ago
9

How many moles of HCl are required to neutralize all 0.050 mol of Ca(OH)2

Chemistry
1 answer:
Andrew [12]3 years ago
8 0
3......................................
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A fixed mass of oxygen gas occupies 300cm cube at 0 degree centigrade. what volume would the gas occupy at 15 degree centigrade​
egoroff_w [7]

Answer:

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

Explanation:

Assuming Pressure is constant.

\frac{V_1}{T_1} = \frac{V_2}{T_2}

where T1 and T2 are temperature in Kelvin

Substituting the give values we get-

\frac{300}{273} = \frac{V_2}{288}

V_2 = \frac{288*300}{273} \\V_2 = 316.5

Volume occupied by oxygen gas at 15 degree centigrade​ is equal to 316.5 centimeter cube

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<span>79.70 grams First, calculate the molar mass of Na2CO3 by looking up the molar mass of the elements used in it. Sodium = 22.989769 Carbon = 12.0107 Oxygen = 15.999 Multiply each molar mass by the number of atoms used, and sum the results to get the molar mass 2 * 22.989769 + 12.0107 + 3 * 15.999 =105.9872 Finally, multiply the molar mass by the number of moles you need. 0.752 * 105.9872 = 79.7024 grams</span>
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