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anastassius [24]
3 years ago
12

A positively charged non-metal ball A is placed near metal ball B. Prove that if the charge on B is positive but of small magnit

ude, the balls will be attracted to each other.
a. The positive charges on the sphere B move to the side closer to sphere A, while the negative charges move to the side further away from sphere A. The polarization of charge on A will cause a greater attractive force than the repulsion of the like charges.

b. The negative charges on the sphere A move to the side closer to sphere B, while the positive charges move to the side further away from sphere B. The polarization of charge on A will cause a greater attractive force than the repulsion of the like charges.

c. The positive charges on the sphere B move to the side closer to sphere A, while the negative charges move to the side further away from sphere A. The polarization of charge on B will cause a greater attractive force than the repulsion of the like charges.

d. The negative charges on the sphere B move to the side closer to sphere A, while the positive charges move to the side further away from sphere A. The polarization of charge on B will cause a greater attractive force than the repulsion of the like charges.
Physics
1 answer:
nordsb [41]3 years ago
8 0

Answer:

D

Explanation:

Ball A is a non positively charged non metal while ball B is metal ball.

Given: The ball B positive charge of small magnitude

To prove: Balls will attract each other

IN this condition because of induction negative charges on the sphere B move to the side closer to sphere A,(induction charging) while the positive charges move to the side further away from sphere A. The polarization of charge on B will cause a greater attractive force than the repulsion of the like charges.

Hence the correct answer will be D .

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Physical sciences grade 11 prescribed experiment 1
Digiron [165]

Answer:  

Newton's second law of motion describes the relationship between force and acceleration. They are directly proportional. If you increase the force applied to an object, the acceleration of that object increases by the same factor. In short, force equals mass times acceleration.

Explanation:

6 0
3 years ago
1. In what year did India (our second most populous country) begin to produce more energy than Spain?
choli [55]

Answers:

<h2>1) Sometime in 2014 </h2>

As we can see in the graph in 2014 there is an intersection between the lines that represent the wind energy production of Spain and India, then the production of India is increased, while that of Spain remains constant.

<h2>2) Germany </h2>

As we can see in the graph in 2000 Germany was the number 1 producer of gigawatts of wind energy. In addition it is observed a rapid growth and increase in production compared to the other countries.

<h2>3) In 2006, America was producing over 10 GW and began a steep climb in wind energy production.</h2>

In 1997, America began with a constant and very small energy production, which was growing gradually until 2006, when its rapid growth in production began to exceed the other countries shown in the graph.

<h2>4) Years</h2>

When a function is plotted, generally the independent variable, whose value is previously set, is represented on the X axis.

In this sense, the variable found on the X axis of this graph is Years.

<h2>5) Wind Energy Capacity </h2>

When a function is plotted, generally the dependent variable (which is generated from the independent variable) is represented on the Y axis.

In this sense, the variable found on the Y axis of this graph is Wind Energy Capacity.

<h2>6) Gigawatts (GW) </h2>

We already know the dependent variable in this <u>Wind Energy Capacity vs Years</u> graph is Wind Energy Capacity, and its Unit is Gigawatts (GW).

Where 1GW=10^{6} W

<h2>7) Both onshore and offshore wind sources </h2>

When we talk about scientific experimentation and representing data, the Control Variable is the one that remains constant (it does not change during the investigation).  

According to the explanation above, the option that fits with this characteristic is: Both onshore and offshore wind sources

<h2>8) 55 GW </h2>

If we want to make a linear interpolation to estimate how much wind energy capacity was there in the United States in the middle of 2011, firstly we need to <u>find two points where the value we want to find is in the middle.</u>

These points (X,Y) are:

P1: (2011,48) and P2: (2012,60)

Where X1:2011, Y1:48, X2:2012, Y2:60

Now we find the <u>slope</u> m of the line with the following equation:

m=\frac{Y2 - Y1}{X2 - X1}

m=\frac{60 - 48}{2012 - 2011}=12

Then, with this value of the slope we can write the <u>equation of the line</u> and find the <u>intersection point</u> b with one of the given points (we will use P1):

Y=mX+b

48=12(2011)+b

b=-24084

With this value and the slope, we can find Y for X=2011.5 (we need to know the wind capacity in the middle of 2011):

Y=(12)(2011.5)-24084

Y=54 This is the e<u>stimated result</u> 54 GW, and the option that is near this value is 55 GW

<h2>9) 36 GW </h2>

In this case we will apply a similar method as the previous answer, but estimating a prediction:

Let's find two points near the value we want to find. These points (X,Y) are:

P1: (2014,22) and P2: (2016,29)

Where X1:2014, Y1:22, X2:2016, Y2:29

Now we find the <u>slope</u> m of the line with the following equation:

m=\frac{Y2 - Y1}{X2 - X1}

m=\frac{29 - 22}{2016 - 2014}=\frac{7}{2}

Then, with this value of the slope we can write the <u>equation of the line</u> and find the <u>intersection point</u> b with one of the given points (we will use P2):

Y=mX+b

29=\frac{7}{2}(2016)+b

b=-7027

With this value and the slope, we can find Y for X=2020 (we need to estimate the expected wind capacity in 2020):

Y=\frac{7}{2}(2020)-7027

Y=43 This is the e<u>stimated result</u> 43 GW (note linear extrapolation is not as accurate as other methods), and the option that is near this value is 36 GW

<h2>10) Additional 7 GW/Year</h2>

In this case we will use the equation of the slope:

m=\frac{Y2 - Y1}{X2 - X1}

With the following points:

P1: (2009,35) and P2: (2016,82)

m=\frac{82 - 35}{2016 - 2009}

m=6.7 \approx 7

Therefore, the correct option is Additional 35 GW/Year

4 0
3 years ago
Two ropes support a load of 478 kg. The two ropes are perpendicular to each other, and the tension in the first rope is 2.2 time
sveta [45]

Answer:

T₂ = 1937.68 N

Explanation:

First, we will calculate the weight of the object:

W = mg = (478\ kg)(9.81\ m/s^2)\\W = 4689.18\ N

Now, we will calculate the resultant tension in the ropes. Since the ropes are perpendicular. Therefore,

T = \sqrt{T_1^2+T_2^2}\\

where,

T = Resultant Tension

T₁ = Tension in rope 1

T₂ = Tension in rope 2

According to the given condition tension in the first rope is 2.2 times the tension in the second rope:

T₁ = 2.2 T₂

Therefore

T = \sqrt{(2.2T_2)^2 + T_2^2}\\\\T =  2.42T_2

Now, the weight of the object must be equal to the resultant tension for equilibrium:

T = W\\2.42T_2 = 4689.18\ N\\\\

<u>T₂ = 1937.68 N</u>

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3 years ago
How much farther from the charge is the 2000 v equipotential surface than the 3000 v surface?
olganol [36]

Answer:

r1 -r2 = 3.75cm

Explanation:

Check the attached file for the solution

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What is the suprising thing that happens in a superconductor
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One of the most surprising things about a superconductor is that
it has NO electrical resistance. The resistance doesn't just become
very very very small.  It becomes literally completely zero. (This is
a big part of the reason why it's called a "super-conductor".)

If you start an electric current flowing in a superconductor, you can
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and around the loop and never dies out !
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3 years ago
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