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gogolik [260]
4 years ago
5

NVM hwaskdhslak djklasj dkjaskj dklasj kJKS KLj klskla

Physics
2 answers:
My name is Ann [436]4 years ago
5 0
Yes, i agree with your statement
svet-max [94.6K]4 years ago
5 0

hwaskdhslak djklasj dkjaskj.

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You hear the sound from a tuning fork vibrating at 483 Hz. You then hear the sound from a second tuning fork vibrating at 512 Hz
AleksAgata [21]

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3 years ago
How can you describe the motion of an object in a race?
Hitman42 [59]
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4 0
3 years ago
A block of concrete has a mass of 48kg a crane lifts the block to a height of 12m above the ground calculate the gravitational p
Afina-wow [57]

Answer:

5760 J

Explanation:

From the question given above, the following data were obtained:

Mass of block = 48 kg

Height (h) = 12 m

Gravitational field strength (g) = 10 N/Kg

Gravitational potential energy (PE) =?

The gravitational potential energy stored by the block can simply be obtained as follow:

PE = mgh

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3 0
3 years ago
65 POINTS! PLEASE ANSWER EVERY QUESTION! NEED HELP ASAP!
otez555 [7]
Maybe you can split up the questions. I will try to answer your first question.

1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)

2. Momentum: p = m₁v₁ + m₂v₂

m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B

Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0

Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0

3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.

4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7

5.You figure out.



3 0
3 years ago
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