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3 years ago

If a man has a made of 83 kilograms on earth, what will the force of gravity on his body on the moon

2 answers:

8 0

kg are units of mass. The acceleration on the moon due to gravity is roughtly 1/6 that of earth. A more precise figure is 1.62 m/s^2

a = 1.62 m/s^2

m = 83 kg

F = ?

F = m * a

F = 83 * 1.62

F = 134.46 Moon's gravitational force on 83 kg man

On earth the force would be 83 * 9.81 = 814.23 Newtons.

Salsk061 [2.6K]3 years ago

7 0

the man would only weigh 13.7 kg on the moon

hope i helped:)

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When serving a tennis ball, a player hits the ball when its velocity is zero (at the highest point of a vertical toss). The racq

Lilit [14]

Answer:60 gm

Explanation:

Given

initial velocity of ball $u=0$

Force exerted by racquet $F=540 N$

time period of force $t=5\ ms$

final velocity of ball $v=45\ m/s$

Racquet imparts an impulse to the ball which is given by

$J=F\Delta t=\Delta P$

$J=540\times \Delta t=m(45-0)$

$m=\frac{540\times 5\times 10^{-3}}{45}$

$m=60\ gm$

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3 years ago

A dockworker applies a constant horizontal force of 90.0 N to a block of ice on a smooth horizontal floor. The frictional force

Oliga [24]

Answer:

The mass of the ice block is equal to 70.15 kg

Explanation:

The data for this exercise are as follows:

F=90 N

insignificant friction force

x=13 m

t=4.5 s

m=?

applying the equation of rectilinear motion we have:

x = xo + vot + at^2/2

where xo = initial distance =0

vo=initial velocity = 0

a is the acceleration

therefore the equation is:

x = at^2/2

Clearing a:

a=2x/t^2=(2x13)/(4.5^2)=1.283 m/s^2

we use Newton's second law to calculate the mass of the ice block:

F=ma

m=F/a = 90/1.283=70.15 kg

6 0

4 years ago

Read 2 more answers

The temperature of the liquid in a container decreases as the liquid evaporates. Use kinetic theory to explain why.

melisa1 [442]

Answer:

Temperature decreases because the number of collision of the molecules decreases as they escape or evaporate. Molecules are in constant motion. Increase in temperature leads to increase in average kinetic energy of the molecules.

6 0

3 years ago

A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback ca

love history [14]

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. $s_{o}$ = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

$v_{i}$ = 33.2 m/s, a = 0 (since the velocity is constant), $s_{o}$ = 0

Using $s =s_{o}+v_{i}t+1/2at^{2}$

s = 33.2t .......... eq (1)

Hatchback:

$a=5m/s^{2}$ , $v_{i}$ = 0 m/s (since initial velocity is zero), $s_{o}$ = 0

Using $s =s_{o}+v_{i}t+1/2at^{2}$

putting in the data we will get

$s=(1/2)(5)t^{2}$

now putting 's' value from eq (1)

$2.5t^{2}-33.2t=0$

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

7 0

3 years ago

Read 2 more answers

A spring scale exerts a net force of 8.5 N on an object. What is the object's mass if it has an acceleration of

Amiraneli [1.4K]

Answer:

mass of the object is 2.18 kg

Explanation:

Given

Force (F) = 8.5 N = 8.5 kg.m/ $s^{2}$

acceleration (a) = 3.9 m/ $s^{2}$

Mass (m) = ?

We know that the newton's second law of motion gives the relation between mass of ab object. force acted upon and the amount the object is accelerated. It is expressed in the form of an equation:

F = ma

mass, m = F/a

= $\frac{8.5 kgms^{-2} }{3.9 ms^{-2} }$

= 2.18 kg

4 0

3 years ago