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Andreas93 [3]
2 years ago
15

The block in the drawing has dimensions L0×2L0×3L0, where L0 =0.5 m. The block has a thermal conductivity of 250 J/(s·m·C˚). In

drawings A, B, and C, heat is conducted through the block in three different directions; in each case, the temperature of the warmer surface is 35 ˚C and that of the cooler surface is 14 ˚C Determine the heat that flows in 2 s for each case.
Physics
1 answer:
stira [4]2 years ago
3 0

Answer:

I am sorry but what drawing

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A glass of water has a temperature of 8°c. in which situation will more energy be transferred, when the air's temperature is 25°
frosja888 [35]
35 because the water will react differntly n get warmer
4 0
3 years ago
The resistance and the magnitude of the current depend on the path that the current takes. The drawing shows three situations in
maria [59]

Answer: (a). Resistance = 0.4286ohms and Current (I) = 7A

(b). Resistance (R) = 0.027 ohms and Current (I) = 111.1A

(c). Resistance (R) = 0.1071 ohms and Current (I) = 28A

Explanation:

From the question, given that;

ρ = 1.5*10-2ῼ.m

Lo = 7cm = 0.07m

V = 3V

From the formula R = ρL/A, where A is the area of cross section, L is the length of material and ρ is the resistivity.

(A)

L = 4Lo and A = 2Lo*Lo

R = ρL/A

R = ρ4Lo/(2Lo*Lo)

R = 2ρ /Lo = 2*1.5*10-2/0.07

R = 0.4286 ῼ

From this the current becomes;

I = V/R = 3/ 0.4286 = 6.99 = 7A

(B)

L = Lo and A = 4Lo * 2Lo

R = ρL/A

R = ρLo/ (4Lo*2Lo) after eliminating Lo from both sides we get,

R = ρ/8Lo = 1.5*10-2 / 8*0.07

R = 0.027

Current (I) = V/R = 3/0.027 = 111.1A

(C)

L = 2Lo and A = Lo * 4Lo

R = ρL/A

R = ρ2Lo/ (Lo*4Lo) eliminating Lo from both sides we get,

R = ρ/2Lo = 1.5*10-2 / 2*0.07 = 0.1071

The current becomes;

I = V/R = 3/0.1071 = 28A

4 0
3 years ago
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Answer:

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B=\frac{\mu_oNi}{L}         (1)

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

N: turns of the solenoid = 580

i: current in the solenoid = 36A

L: length of the solenoid = 18cm = 0.18m

You replace the values of all parameters in the equation (1):

B=\frac{(4\pi*10^{-7}T/A)(580)(36A)}{0.18m}=0.145T

Next, you calculate the force exerted on the wire, by using the following formula:

F=iLBsin\theta         (2)

i: current in the wire = 27A

L: length of the wire that perceives the magnetic field (the same as the radius of the solenoid) = 2.0 cm = 0.02m

θ: angle between wire and the direction of B

B: magneitc field in the solenoid = 0.145T

The direction of the wire are perpendicular to the direction of the magnetic field, hence, the angle is 90°.

You replace the values of the parameters in the equation (2):

F=(27A)(0.02m)(0.145T)sin90\°=0.078N

The magnitude of the force on the wire is 0.078N

8 0
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Which best explains why a wood-burning fireplace represents an open system?
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The answer will be B
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