Hi there!
Recall the equation for electric potential of a point charge:

V = Electric potential (V)
k = Coulomb's Constant(Nm²/C²)
Q = Charge (C)
r = distance (m)
We can begin by solving for the given electric potentials. Remember, charge must be accounted for. Electric potential is also a SCALAR quantity.
Upper right charge's potential:

Lower left charge's potential:

Add the two, and subtract from the total EP at the point:

The remaining charge must have a potential of 2036.25 V, so:

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Answer:
F=ma
here F is force, m is mass and a is accelaration,
According to the question,
F=3*F= 3F
m= 1/3 of m= m/3
a= ?
so the equation becomes,
3F= m/3*a
3F*3= ma
9F=ma
F= ma/9
Therefore accelaration reduces by 1/9.
I am not very sure.
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