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3 years ago

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Which of the following molecules has correctly labeled bond dipoles?

1 answer:

Pepsi [2]3 years ago

8 0

The bond dipole moment<span> uses the idea of </span>electric dipole moment<span> to measure the </span>polarity<span> of a chemical bond within a </span>molecule<span>. It occurs whenever there is a separation of positive and negative charges. In the diagram above, option B exhibited a bond dipole moment. I hope this helps.</span>

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5. Chlorine gas was formed at the ... *

Marat540 [252]

Clorine gas was formed at the <em><u>positive</u></em><em><u> </u></em><em><u>electrode</u></em><em><u>.</u></em><em><u> </u></em>

5 0

3 years ago

Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 28.7 moles of FeO. Y

Alexxx [7]

Answer:

43.05 moles of Al needed to react with 28.7 moles of FeO.

Explanation:

Given data:

Moles of FeO = 28.7 mol

Moles of Al needed to react with FeO = ?

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Now we will compare the moles of Al with FeO.

FeO : Al

2 : 3

28.7 : 3/2×28.7 = 43.05 mol

Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.

8 0

3 years ago

What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?

Colt1911 [192]

Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.

Explanation:

d = m/V, where d is the density, m is the mass and V is the volume.

We have the mass m = 0.50 g, so we must get the volume V.

To get the volume of a gas, we apply the general gas law PV = nRT

P is the pressure in atm (P = 1.5 atm)

V is the volume in L (V = ??? L)

n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).

Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.

Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.

6 0

4 years ago

Which chemical equation below is balanced correctly?

Sveta_85 [38]

Al4C3 + 12H2O-----> 3CH4 + 4Al(OH)3

8 0

3 years ago

Read 2 more answers

The equilibrium constant, K, for the following reaction is 5.10X10 at 548 K. NH_CH(s) 2 NH3(E) + HC1(2) Calculate the equilibriu

Serga [27]

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = $K_c=5.10\times 10^{-6}$

Moles of ammonium chloride = 0.573 mol

Concentration of ammonium chloride = $\frac{0.573 mol}{1.00 L}=0.573 M$

$NH_4HCl(s)\rightleftharpoons 2 NH_3(g) + HCl(g)$

Initial: 0.573 0 0

At eq'm: (0.573-x) x x

We are given:

$[NH_4Cl]_{eq}=(0.573-x)$

$[HCl]_{eq}=x$

$[NH_3]_{eq}=x$

Calculating for 'x'. we get:

The expression of $K_{c}$ for above reaction follows:

$K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}$

Putting values in above equation, we get:

$5.10\times 10^{-6}=\frac{x\times x}{(0.573-x)}$

$2.9223\times 10^{-6}-5.10x\times 10^{-6}=x^2$

$x^2-2.9223\times 10^{-6}+(5.10\times 10^{-6})x=0$

On solving this quadratic equation we get:

x = 0.01707 M

The equilibrium concentration of HCl is 0.01707 M.

3 0

3 years ago