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Naddik [55]
2 years ago
11

What is the formula of the compound formed between chlorine and calcium?

Chemistry
1 answer:
VLD [36.1K]2 years ago
5 0

the formula  of the compound that  is formed  between  chlorine and calcium  is CaCl2


explanation

chlorine (non  metal)  react  with Calcium ( a metal)  to  form an ionic compound  CaCl2

Ionic compound   is formed when metal  loses electrons to form cation ( a  positively charged ion)  while  non metal  gains electrons  to  form anion (  a  negatively  charged ion)

An ionic compound is formed when calcium   metal(Ca) loses two electron to form   Ca2+ cation ,  while   2 chlorine atom  gain  one electron each to form cl- anions.


  • when writing  down  the formula  of ionic compound  cation  symbol  is written first  followed by  anion symbol.

Therefore the formula  of ionic compound formed between chlorine  and calcium is CaCl2

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Which term describes the composition of matter shown in figure A
bija089 [108]

Answer:

The answer to your question is Element

Explanation:

Element is a substance whose atoms are all the same because of all the atoms

              have the same number of protons, neutrons and, electrons.

Compound is a substance formed when 2 or more atoms combined.

Mixture  is a substance formed by 2 or more different kinds of atoms or

              compounds.

Phase   is a state of matter like solid, liquid or gas.

According to the definitions, we conclude that the figure is an Element.

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3 years ago
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1. a 2.b 3 a 4. c. 4.a 5. d 6.a. 2Na + Cl2 2NaC 7.c. 3 8.3 9.b
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Calculate the molarity when 135 g of KCl is dissolved to make a 2.50 L solution. Round to two significant digits.
inysia [295]
<h2>0.72 mol/L</h2>

Explanation:

       \textrm{Molarity of a solution}=\frac{\textrm{Number of moles of solvent}}{\textrm{Volume of solution in Liters}}

       We are given a 2.50L solution which contains 135g of KCl.

       To calculate number of moles of KCl present, we need to find it's molar mass from charts. Molar Mass of KCl is known to be 74.55\frac{g}{Mol}.

       Number of moles of KCl present = \frac{\textrm{Given weight}}{\textrm{Molar Mass}}\textrm{ = }\frac{135g}{74.55\frac{g}{Mol}}\textrm{ = }1.81087mol

       Molarity = \frac{1.81087mol}{2.50L}=0.7243\frac{mol}{L}

∴ Molarity of given KCl solution = 0.72\frac{mol}{L}

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