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SIZIF [17.4K]
3 years ago
11

Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 28.7 moles of FeO. Y

ou must show all of your work. 2Al + 3FeO --> 3Fe +Al2O3
Chemistry
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

43.05 moles of Al needed to react with 28.7 moles of FeO.

Explanation:

Given data:

Moles of FeO = 28.7 mol

Moles of Al needed to react with FeO = ?

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Now we will compare the moles of Al with FeO.

                            FeO        :           Al

                             2            :            3

                          28.7          :         3/2×28.7 = 43.05 mol

Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.

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En el enlace covalente entre azufre y carbono (6 y 4 electrones en su ultima capa respectivamente) la molécula tendrá ?
d1i1m1o1n [39]

Answer:

a- Uno de carbono y dos de azufre

Explanation:

El compuesto formado entre el carbono y el azufre es CS2.

El carbono forma dos enlaces dobles con dos átomos de azufre.

Por lo tanto, el compuesto contiene un átomo de carbono y dos átomos de azufre.

6 0
3 years ago
A beaker contains 500 ml of 2.40M KNO3 the beaker is left uncovered so that all of the water evaporates. What mass of KNO3 cryst
telo118 [61]

Answer:

242.4 g

Explanation:

RAM of KNO3=39+14+(16×3)=101

Mass=morality×RAM

101*2.4=242.4

6 0
3 years ago
If you wanted to find a sample of fermium, which has an atomic number 100, where would you look?
sergeinik [125]
The answer would be B: In the Earth’s atmosphere!.

Hope this helps,
7 0
3 years ago
Determine the volume of a substance that has a density of 1.84 g/ml and a mass of 12 grams
vazorg [7]
Hey there!:

density = mass / volume

1.84 g/mL =  12 g / V

V =  12 / 1.84

V = 6.521 mL

hope this helps!
             
5 0
3 years ago
2. A sample of neon gas has a volume of 87.6 L at STP. How many moles are present?
PSYCHO15rus [73]

Answer:

                      3.91 moles of Neon

Explanation:

According to Avogadro's Law, same volume of any gas at standard temperature (273.15 K or O °C) and pressure (1 atm) will occupy same volume. And one mole of any Ideal gas occupies 22.4 dm³ (1 dm³ = 1 L).

Data Given:

                 n = moles = <u>???</u>

                 V = Volume = 87.6 L

Solution:

               As 22.4 L volume is occupied by one mole of gas then the 16.8 L of this gas will contain....

                          = ( 1 mole × 87.6 L) ÷ 22.4 L

                          = 3.91 moles

<h3>2nd Method:</h3>

                     Assuming that the gas is acting ideally, hence, applying ideal gas equation.

                              P V  =  n R T      ∴  R  =  0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹

Solving for n,

                              n  =  P V / R T

Putting values,

                              n  =  (1 atm × 87.6 L)/(0.08205 L⋅atm⋅K⁻¹⋅mol⁻¹ × 273.15K)

                              n  =  3.91 moles

Result:

          87.6 L of Neon gas will contain 3.91 moles at standard temperature and pressure.

7 0
3 years ago
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