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SIZIF [17.4K]
3 years ago
11

Given the balanced equation below, calculate the moles of aluminum that are needed to react completely with 28.7 moles of FeO. Y

ou must show all of your work. 2Al + 3FeO --> 3Fe +Al2O3
Chemistry
1 answer:
Alexxx [7]3 years ago
8 0

Answer:

43.05 moles of Al needed to react with 28.7 moles of FeO.

Explanation:

Given data:

Moles of FeO = 28.7 mol

Moles of Al needed to react with FeO = ?

Solution:

Chemical equation:

2Al + 3FeO → 3Fe + Al₂O₃

Now we will compare the moles of Al with FeO.

                            FeO        :           Al

                             2            :            3

                          28.7          :         3/2×28.7 = 43.05 mol

Thus 43.05 moles of Al needed to react with 28.7 moles of FeO.

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Explanation:

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B) 5P + 4O₂    →    2P₄O₅

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This equation is not balanced. There are two phosphorus, two oxygen atoms on left and two phosphorus five oxygen on right side of equation.

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11111nata11111 [884]

Answer:

\large \boxed{\text{460 dg}}

Explanation:

1. Convert decagrams to grams

\text{Mass} =  \text{4.6 dag} \times\dfrac{\text{10 g}}{\text{1 dag}} = \text{46 g}

2. Convert grams to decigrams

\\text{Mass} =  \text{46 g} \times\dfrac{\text{10 g}}{\text{1 dg}} = \text{460 dg}\\\\\large \boxed{\textbf{4.6 dag = 460 dg}}

3 0
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Answer:

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