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2 years ago

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A sanding disk with rotational inertia 2.0 x 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of magnit

ude 11 N·m about the central axis of the disk. About that axis and with torque applied for 19 ms, what is the magnitude of the (a) angular momentum and (b) angular velocity of the disk?

1 answer:

Inessa05 [86]2 years ago

4 0

Answer

Given,

Rotational inertia = 2.0 x 10-3 kg·m²

Torque = 11 N.m

time, t = 19 ms

a) Angular momentum

$\tau = \dfrac{\Delta L}{\Delta t}$

L is angular momentum

$\Delta L = \tau \Delta t$

$\Delta L = 11\times 19 \times 10^{-3}$

$\Delta L = 0.209\ Kg m^2/s$

b) Angular velocity

We know.

$L = I \omega$

$\omega = \dfrac{L}{I}$

$\omega = \dfrac{0.209}{2\times 10^{-3}}$

$\omega = 104.5\ rad/s$

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3 years ago

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The rest of the question is written below:

a. What is the final speed of the falcon and pigeon?

b. What is the average force on the pigeon during the impact?

<h3>a) Final speed</h3>

This part can be solved by the Conservation of linear momentum principle, which establishes the initial momentum $p_{i}$ before the collision must be equal to the final momentum $p_{f}$ after the collision:

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Where:

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In this part we will use the following equation:

$F=\frac{\Delta p}{\Delta t}$ (6)

Where:

$F$ is the force exerted on the pigeon

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Substituting (8) in (6):

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